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3 years ago

Translate the statement into an inequality 5 more than a number is greater than 12

Mathematics

1 answer:

nika2105 [10]3 years ago

8 0

Step-by-step explanation:

Let the number be x.

$\therefore \: x + 5 > 12$

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Do u know something about Find the quotient.?

denis23 [38]

Answer:

17 divided by 3, the quotient is 5

Step-by-step explanation:because 3x5 is 15 and you cannot go furhter than that.

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2 years ago

(help) Miller’s Farm had apples on sale for $1.78 a pound. Maria spent $15.21 on apples. How many pounds did she buy?

jolli1 [7]

Answer:

8.5 pounds

Step-by-step explanation:

$ 1.78 - 1 pound

$ 15.21 - 15.21/1.78

= 8.5

5 0

2 years ago

Find the area of the figure below

satela [25.4K]

Answer:

The total area is 300 ft^2

Step-by-step explanation:

First find the area of the rectangle

A = l*w = 24*10 = 240

Then find the area of the triangle on the top

A = 1/2 bh

The base is 24 and the height is 15-10 = 5

A = 1/2 (24)*5 = 60

Add them together

240+60 = 300

The total area is 300 ft^2

7 0

3 years ago

Read 2 more answers

If c is 5, then 6x =

Firlakuza [10]

Answer:

Step-by-step explanation:

because if x is 5 then 6(5)

and 6x5=30

5 0

3 years ago

(x^2 - x^(1/2))/(1-x^(1/2))

Levart [38]

$\frac { \left( { x }^{ 2 }-{ x }^{ \frac { 1 }{ 2 } } \right) }{ \left( 1-{ x }^{ \frac { 1 }{ 2 } } \right) }$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot 1$

$\\ \\ =\frac { \left( { x }^{ 2 }-\sqrt { x } \right) }{ \left( 1-\sqrt { x } \right) } \cdot \frac { \left( 1+\sqrt { x } \right) }{ \left( 1+\sqrt { x } \right) }$

$\\ \\ =\frac { { x }^{ 2 }+{ x }^{ 2 }\sqrt { x } -\sqrt { x } -x }{ 1+\sqrt { x } -\sqrt { x } -x }$

$\\ \\ =\frac { -\sqrt { x } \left( 1-{ x }^{ 2 } \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { -\sqrt { x } \left( 1+x \right) \left( 1-x \right) -x\left( 1-x \right) }{ \left( 1-x \right) }$

$\\ \\ =\frac { \left( 1-x \right) \left\{ -\sqrt { x } \left( 1+x \right) -x \right\} }{ \left( 1-x \right) }$

$\\ \\ =-\sqrt { x } \left( 1+x \right) -x\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }\left( 1+{ x }^{ \frac { 2 }{ 2 } } \right) -x$

$\\ \\ =-{ x }^{ \frac { 1 }{ 2 } }-{ x }^{ \frac { 3 }{ 2 } }-x\\ \\ =-\sqrt { x } -\sqrt { { x }^{ 3 } } -x$

3 0

3 years ago

Read 2 more answers