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zloy xaker [14]

1 year ago

11

If a rectangle has a length of 5in, a width of 4in, and a height of 8in.Evaluate the volume using the formula: V=LWH 20 inches c

ubedO 40 inches cubed60 inches cubed0 160 inches cubed

1 answer:

ozzi1 year ago

5 0

Substitute the numbers in the equation:

$V=LWH$

Since L=5in, W=4in and H=8in:

$\begin{gathered} V=(5in)(4in)(8in) \\ =160in^3 \end{gathered}$

Therefore, the volume is equal to 160 inches cubed.

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The square root of 9x^4/36 simplified

Serggg [28]

Step-by-step explanation:

$\sqrt{ \frac{9 {x}^{4} }{36} } \\ \\ = \sqrt{ \frac{ {x}^{4} }{4} } \\ \\ = \frac{ {x}^{2} }{2}$

6 0

3 years ago

Solve the 3 × 3 system shown below. Enter the values of x, y, and z. X + 2y – z = –3 (1) 2x – y + z = 5 (2) x – y + z = 4 (3)

Svet_ta [14]

<h2>Answer:</h2>

$\boxed{x=1, \y=-1, \ z=2}$

<h2>Step-by-step explanation:</h2>

We will use the Gaussian elimination method to solve this problem. To do so, let's follow the following steps:

Step 1: Let's multiply first equation by −2. Next, add the result to the second equation. So:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\~~ x&-~~~~~ y&+~~~~ z&~=~4\end{array}$

Step 2: Let's multiply first equation by −1. Next, add the result to the third equation. Thus:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&-~~~3~ y&+~~2~ z&~=~7\end{array}$

Step 3: Let's multiply second equation by −35, Next, add the result to the third equation. Therefore:

$\begin{array}{ cccc }~~ x&+~~2~ y&-~~~~~ z&~=~-3\\&-~~~5~ y&+~~3~ z&~=~11\\&&+~~\frac{ 1 }{ 5 }~ z&~=~\frac{ 2 }{ 5 }\end{array}$

Step 4: solve for z, then for y, then for x:

$\frac{ 1 }{ 5 } ~ z & = \frac{ 2 }{ 5 } \\ \\ \boxed{z & = 2}$

$-5y+3z &= 11\\-5y+3\cdot 2 &= 11\\ \\ \boxed{y &= -1}$

By substituting $y=-1 \ and \ z=2$ into the first equation, we get the $x$ . So:

$x+2(-1)-2=-3 \\ \\ x-2-2=-3 \\ \\ \boxed{x=1}$

6 0

3 years ago

Read 2 more answers

Evaluate cos 25o to four decimal places.

Firdavs [7]

$\tt \cos(25) = 0.991203 \: or \: 0.99$

8 0

1 year ago

Explain two ways to find the LCM

svp [43]

Answer:

1. List the first several multiples of each number.

Look for multiples common to both lists. ...

Look for the smallest number that is common to both lists.

This number is the LCM.

Find the GCF for the two numbers.

Divide that GCF into the either number; it doesn't matter which one you choose, so choose the one that's easier to divide.

Take that answer and multiply it by the other number.

Step-by-step explanation:

Hope this helps!

4 0

2 years ago

The height of a trapezoid is 6 in. and it’s area is 72 in to the 2nd power. One base of the trapezoid is 6 inches longer than th

Vitek1552 [10]

Given:

The height of the given trapezoid = 6 in

The area of the trapezoid = 72 in²

Also given, one base of the trapezoid is 6 inches longer than the other base

To find the lengths of the bases.

Formula

The area of the trapezoid is

$A=\frac{1}{2} (b_{1} +b_{2} )h$

where, h be the height of the trapezoid

$b_{1}$ be the shorter base

$b_{2}$ be the longer base

As per the given problem,

$b_{2}=b_{1} +6$

Now,

Putting, A=72, $b_{2}=b_{1}+6$ and h=6 we get,

$\frac{1}{2} (b_{1} +b_{1}+6)(6) = 72$

or, $b_{1}+b_{1}+6 = \frac{(72)(2)}{6}$

or, $2b_{1}+6 = 24$

or, $2b_{1}=24-6$

or, $b_{1}= \frac{18}{2}$

or, $b_{1}=9$

So,

The shorter base is 9 in and the other base is = (6+9) = 15 in

Hence,

One base is 9 inches for one of the bases and 15 inches for the other base.

5 0

3 years ago