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ratelena [41]
2 years ago
11

(7y – 20) (5х – 38) (3х – 4) - m

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

um

Step-by-step explanation:

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BRAINLIEST GOING TO THE FIRST ANSWER
Lesechka [4]

Answer:

w + 2.3 > 18

Step-by-step explanation:

MARK ME BRAINLIEST!!!!!!!!!

5 0
3 years ago
Read 2 more answers
Ivan rented a truck for the day. There is a base fee of $17.95, and there was an additional charge of 91 cents for each mile dri
lozanna [386]

Answer:

293 miles

Step-by-step explanation:

284.58-17.95=266.63

266.63/0.91=293

293 miles

7 0
3 years ago
Can someone just explain to me how to do this please
Dmitrij [34]

Answer: -7.5

Step-by-step explanation:

area = 1/2bh.

area = 1/2(x+6)(5)

area = x/2 + 15

area = x/2 = -15

area = x = -7.5

area = -7.5

5 0
3 years ago
Dan buys a car for £2100.
SVETLANKA909090 [29]

Answer:

£1837.5

Step-by-step explanation:

Given data

Cost of car P=  £2100.

Rate r= 2.2%

Time t= 6 years

Now we want to find the  worth after 6 years, let us apply the compound interest expression but this time for depreciation

A= P(1-r)^t

Substitute

A= 2100(1-0.022)^6

A= 2100*(0.978)^6

A= 2100*0.875

A= £1837.5

Hence the amount of the car after 6 years is £1837.5

8 0
3 years ago
Robert went to the grocery store and purchased cans of soup and frozen dinners. each can of soup has 300 mg of sodium and each f
Paraphin [41]

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Step-by-step explanation:

Let,

Soup = x

Frozen Dinner = y

According to given statement of sodium;

300x + 500y = 5200 eqn 1

And,

x + y = 14 eqn 2

Multiplying\ equation\ 2\ with\ 300\\300(x+y=14)\\300x+300y=4200\ Eqn 3\\

Subtracting Eqn 3 from Eqn 1;

(300x+500y)-(300x+300y)=5200-4200\\300x+500y-300x-300y=1000\\200y=1000\\y=\frac{1000}{200} \\y=5

Putting value of y in Eqn 1;

300x+500(5)=5200\\300x+2500=5200\\\\Subtracting\ 2500\ from\ both\ sides\ \\300x+2500-2500=5200-2500\\300x=2700\\x=\frac{2700}{300} \\x=9

There are 9 cans of soup and 5 cans of frozen dinner.

The variables used for soup and frozen dinner are x and y respectively.

Keywords: Variables, linear equations, subtraction.

Learn more about linear equations at;

  • brainly.com/question/5047646
  • brainly.com/question/5048216

#LearnwithBrainly

5 0
3 years ago
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