(7y – 20) (5х – 38) (3х – 4) - m
1 answer:
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The cattle train
speed - 36.5 km/h
time - x h
the passenger train
speed - 29.2 km/h
time - (2.4+x) h
The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.
The passenger train travelled for 12 hours before the cattle train caught up.
speed - 36.5 km/h
time - x h
the passenger train
speed - 29.2 km/h
time - (2.4+x) h
The cattle train caught up to the passenger train so the distance they travelled is the same.
Distance is speed times time.
The passenger train travelled for 12 hours before the cattle train caught up.
