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olya-2409 [2.1K]
1 year ago
15

Suppose that the mean and standard deviation of the scores in a Statistics exam are 75 and 9.5 respectively. What minimum score

should a student obtain to be a part of the top 2.5%? Round answers to 2 decimal places.
Mathematics
1 answer:
lyudmila [28]1 year ago
8 0

The mean and standard deviation of the scores are 75 and 9.5 respectively.

The z-score is a means to find the probability of getting a particular score. This is calculated to be:

z=\frac{x-\mu}{\sigma}

where x is the score, μ is the mean, and σ is the standard deviation.

To be a part of the top 2.5 percent, the probability is:

P=\frac{2.5}{100}=0.025

The z-score for this probability, that is, P

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Guys I am going to run out of points. Help with 19?<br> I don't need an explanation.
nasty-shy [4]

Answer:

A.) 20x + 2y = 500

B.) y-intercept = 250; its meaning is how many boxes of pencils they started with.

C.) x-intercept = 25; How many T-shirts they can sell at most

Step-by-step explanation:

2y - 500 = -20x

20x + 2y - 500 = 0

20x + 2y = 500

y-intercept = 250; its meaning is how many boxes of pencils they started with.

20x + 2y = 500

20(0) + 2y = 500

2y = 500

2y/2 = 500/2

y = 250

x-intercept = 25; How many T-shirts they can sell at most

20x + 2y = 500

20x + 2(0) = 500

20x = 500

20x/20 = 500/20

x = 25

4 0
3 years ago
How to simplify fully
iren2701 [21]
.that's how 2 solve it

4 0
3 years ago
Put -9.3 and -4.125 and -2.25 in order from least to greatest
DedPeter [7]
It would be : -9.3 , -4.125 and -2.25.

Hope This Helps You!
Good Luck Studying :)
7 0
3 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
A car traveled at an average rate of 51 miles per hour on one highway. It then traveled at an average rate of 71 miles per hour
sergiy2304 [10]

d1 = 51(t)

d2 = 71(8 - t)

d1 + d2 = 508

and now you just have to solve for t.

3 0
3 years ago
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