Answer
B
Explanation
Because it has the same shot and long side
Complete question :
Suppose someone gives you 8 to 2 odds that you cannot roll two even numbers with the roll of two fair dice. This means you win $8 if you succeed and you lose $2 if you fail. What is the expected value of this game to you? What can you expect if you play 100 times.
Answer:
$0.5 ; win $50 with 100 rolls
Step-by-step explanation:
From a roll of two fair dice; probability of obtaining an even number :
Even numbers = (2, 4, 6) = 3
P = 3 /6 = 1 /2
For 2 fair dice ; probability of rolling two even numbers : independent event.
1/2 * 1/2 = 1/4
Hence, p(success) = 1/4 ; P(failure) = 1 - 1/4 = 3/4
Probability table
Winning = $8 or loss = - $2
X : ____ 8 ______ - 2
P(x) __ 1/4 ______ 3/4
Expected value : E(x) = ΣX*P(x)
E(x) = (8 * 1/4) + (-2 * 3/4)
E(x) = 2 - 1.5
E(x) = $0.5
Since expected value is positive, the expect to win
If played 100 times;
Expected value = 100 * $0.5 = $50
She would have sold 45 tickets on the first day
Neato
um
requires some trial and error
erm
ah hah
what 2 numbers multiply to get 16 and add to get -8
-4 and -4
(x-4y)(x-4y)
(x-4y)²
Answer:
The area of the roof: ≈2287.44 ft^2, the lateral area of the roof:≈1580.58 ft^2
Step-by-step explanation:
The area of the roof is computed by the equation of the area of a cone:
A = πr(r + 
)
(r: radius, h: height, πr^2 is the area of the base of the cone, πr is the lateral area of the cone). So:
A = 
≈ 2287.44 ft^2.
As I stated earlier, the lateral area of the roof can be computed:
A
=
≈ 1580.58 ft^2.
