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Free_Kalibri [48]
3 years ago
9

In the diagram bisectors of triangle ABC meet at point G. Find BG.

Mathematics
1 answer:
dusya [7]3 years ago
5 0

Answer:

25

Step-by-step explanation:

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A researcher is exploring the notion that there is an economy of scale in raising children. While having one child might add to
trasher [3.6K]

Answer:

The probability is   G  =  85%

Step-by-step explanation:

From the question we are told that

   The percentage of parents that have one child under 18 in their homes is  k = 15%

  The percentage of parents that have two children is  T = 65%

    The percentage of parents that have three or more children is  Y = 20%

Generally the probability that any given family who is selected have two or more children at home is mathematically evaluated as

     G  =  T  +  Y

=>  G  =  65% +  20%

=>  G  =  85%

4 0
3 years ago
Rita had $9.00. She spent $3.67 on a magazine.
Ket [755]
She has $5.33 left


$9.00
-$3.67
————
$5.33
8 0
2 years ago
Read 2 more answers
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Identify whether the following equation has a unique solution, no solution, or infinitely many solutions.
lidiya [134]

Answer:

No solution

Step-by-step explanation:

3+6=9

3-4=-1

9 doesn't equal -1 therefore no solution.

3 0
2 years ago
Write an equation<br> Slope:0<br> Y-intercept:9
Aneli [31]

Answer:

y=9

Step-by-step explanation:

4 0
3 years ago
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