Answer:
x=12
Step-by-step explanation: brainest pls
Answer: 0.0475
Step-by-step explanation:
Let x = random variable that represents the number of a particular type of bacteria in samples of 1 milliliter (ml) of drinking water, such that X is normally distributed.
Given: 
The probability that a given 1-ml will contain more than 100 bacteria will be:
![P(X>100)=P(\dfrac{X-\mu}{\sigma}>\dfrac{100-85}{9})\\\\=P(Z>1.67)\ \ \ \ [Z=\dfrac{X-\mu}{\sigma}]\\\\=1-P(Zz)=1-P(Z](https://tex.z-dn.net/?f=P%28X%3E100%29%3DP%28%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%3E%5Cdfrac%7B100-85%7D%7B9%7D%29%5C%5C%5C%5C%3DP%28Z%3E1.67%29%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7BX-%5Cmu%7D%7B%5Csigma%7D%5D%5C%5C%5C%5C%3D1-P%28Z%3C1.67%29%5C%20%5C%20%5C%20%5BP%28Z%3Ez%29%3D1-P%28Z%3Cz%29%5D%5C%5C%5C%5C%3D1-%200.9525%3D0.0475)
∴The probability that a given 1-ml will contain more than 100 bacteria
0.0475.
The approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°
<h3>Law of Cosines</h3>
From the question, we are to determine the approximate measure of angle T
From the law of cosines, we can write that
cosT = (s² + u² - t²)/2su
From the diagram,
s = 3.9 cm
u = 2.7 cm
t = 4.3 cm
Thus,
cosT = (3.9² + 2.7² - 4.3²)/2(3.9)(2.7)
cosT = (15.21 + 7.29 - 18.49)/21.06
cosT = 4.01/21.06
cosT = 0.1904
T = cos⁻¹(0.1904)
T = 79.02°
T ≈ 79°
Hence, the approximate measure of angle T in the given diagram is 79°. The correct option is the first option 79°
Learn more on Law of Cosines here: brainly.com/question/28081595
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The asymptote of g(x) is the aymptote of f(x) shifted six units up
