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1 year ago

identify any outliers present in the graph starting at the bottom of the graph and working your way up

Mathematics

1 answer:

oee [108]1 year ago

5 0

Given a scatter plot, the outliers are the points that do not follow the same orientation as the rest of the data points.

Looking from left to right, in this case, we can see that the first outlier is the point (100,80) and the second outlier is the point (160,30)

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What is the slope of the line through (-7, -2) and (-6, 7)?

Reil [10]

Answer:

$\displaystyle =9$

Step-by-step explanation:

The slope formula is

$\displaystyle \frac{y_2-y_1}{x_2-x_1}$

$\displaystyle y_2=7\\\displaystyle y_1=(-2)\\\displaystyle x_2=(-6)\\\displaystyle x_1=(-7)$

$\frac{7-(-2)}{(-6)-(-7)}=\frac{9}{1}=9$

Therefore, the slope is 9, and the correct answer is 9.

Hope this helps!

8 0

3 years ago

Read 2 more answers

Simplify. √144a^2 b^4 c^6

34kurt

Answer:

$12ab^2c^3$

Step-by-step explanation:

$\sqrt{144a^2b^4c^6} =12ab^2c^3$

7 0

3 years ago

Read 2 more answers

Gas is escaping from a spherical balloon at the rate of 12 ft3/hr. At what rate (in feet per hour) is the radius of the balloon

bija089 [108]

Answer:

This is the rate at which the radius of the balloon is changing when the volume is 300 $ft^3$ $\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \:\frac{ft}{h} \approx -0.05537 \:\frac{ft}{h}$

Step-by-step explanation:

Let $r$ be the radius and $V$ the volume.

We know that the gas is escaping from a spherical balloon at the rate of $\frac{dV}{dt}=-12\:\frac{ft^3}{h}$ because the volume is decreasing, and we want to find $\frac{dr}{dt}$

The two variables are related by the equation

$V=\frac{4}{3}\pi r^3$

taking the derivative of the equation, we get

$\frac{d}{dt}V=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4}{3}\pi (3r^2)\frac{dr}{dt} \\\\\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}$

With the help of the formula for the volume of a sphere and the information given, we find $r$

$V=\frac{4}{3}\pi r^3\\\\300=\frac{4}{3}\pi r^3\\\\r^3=\frac{225}{\pi }\\\\r=\sqrt[3]{\frac{225}{\pi }}$

Substitute the values we know and solve for $\frac{dr}{dt}$

$\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=-\frac{12}{4\pi (\sqrt[3]{\frac{225}{\pi }})^2} \\\\\frac{dr}{dt}=-\frac{3}{\pi \left(\sqrt[3]{\frac{225}{\pi }}\right)^2}\\\\\frac{dr}{dt}=-\frac{3}{\pi \frac{225^{\frac{2}{3}}}{\pi ^{\frac{2}{3}}}}\\\\\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \approx -0.05537 \:\frac{ft}{h}$

7 0

4 years ago

Please help answer this question! I will mark brainliest, and greatly appreciate your help!

Nataly [62]

Answer:

15°

Step-by-step explanation:

sorry if I'm wrong but I think you need to add up all the ° and then subtract that number from 100 to get your answer in which in this case the answer would be 15°

3 0

3 years ago

SOME ONE PLEASE HELP!!!<br> if you can, please show your work. thank you.

miskamm [114]

Answer:

315

Step-by-step explanation:

If i understand this correctly, you just need to get the volume of the box and divide it by the volume of the 1/2 cube to see how many will fit.

# 1/2in cubes = (5.25 * 3 * 2.5)/(0.5 * 0.5 * 0.5)

# 1/2in cubes = (39.375)/(0.125) = 315

6 0

3 years ago