Total number of outcomes = 6
Number of ways the event occurs = 5
Probability = 5/6
3987/240=16.6125
So he would need 17 Cases/Boxes to fit the cans.
Answered by /\///\/_//\
Answer:
Step-by-step explanation:
I answered your question in #24317186. Apparently you asked it twice and no one helped you yesterday.
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Answer:
Option a. $2,040
Step-by-step explanation:
step 1
To find out the amount of the additional passive income last year, subtract the amount earned at her salaried job from Loretta’s income last year
so
step 2
Divide the additional passive income last year by 12 (number of months in a year)
therefore
approximately $2,400 per month
