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Ainat [17]
2 years ago
12

Triangle ABC is congruent to triangle DFE. Find x.

Mathematics
2 answers:
Sever21 [200]2 years ago
8 0

Answer:

x=33    

Step-by-step explanation:

We have been given given that triangle ABC is congruent to triangle DFE. We are asked to find the value of x.

Since triangle ABC is congruent to triangle DEF, so:

\overline{AB}=\overline{DF}

\overline{CA}=\overline{ED}      

\overline{BC}=\overline{FE}  

Upon substituting the value of BC and FE in equation, we will get:

20=x-13  

Switch sides:

x-13=20  

Add 13 on both sides:

x-13+13=20+13  

x=33    

Therefore, the value of x is 33 for our given triangles.

jarptica [38.1K]2 years ago
6 0
Since side BC must equal FE, x - 13 = 20. Therefore x = 33
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3 years ago
An art museum has a pentagon-shaped room. When drawn to scale on a coordinate grid, the corners of the room are points (18,20):
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Answer:

2\ gal

Step-by-step explanation:

we know that

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

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A(18,20),B(4,20)

substitute in the formula

d=\sqrt{(20-20)^{2}+(4-18)^{2}}

d=\sqrt{(0)^{2}+(-14)^{2}}

AB=14\ ft

step 2

Find the distance BC

we have

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substitute in the formula

d=\sqrt{(4-20)^{2}+(4-4)^{2}}

d=\sqrt{(-16)^{2}+(0)^{2}}

BC=16\ ft

step 3

Find the distance DE

we have

D(16.2),E(22.10)

substitute in the formula

d=\sqrt{(10-2)^{2}+(22-16)^{2}}

d=\sqrt{(8)^{2}+(6)^{2}}

d=\sqrt{100}

DE=10\ ft

step 4

Find the distance AE

we have

A(18,20),E(22.10)

substitute in the formula

d=\sqrt{(10-20)^{2}+(22-18)^{2}}

d=\sqrt{(-10)^{2}+(4)^{2}}

d=\sqrt{116}

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step 5

Find out the area of the four walls

To determine the area sum the length sides and multiply by the height of the walls

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A=(AB+BC+DE+AE)h

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A=(50.77)10

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step 6

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we know that

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using proportion

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kifflom [539]
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Hope this helps!
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zubka84 [21]
(4,7)(0,7)

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