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disa [49]
3 years ago
8

Number 19 and number 20 please

Mathematics
1 answer:
aev [14]3 years ago
3 0
F(-1)=3(-1)-5=-3=5=-8
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.The price of a MP3 Player decreases from $382 to $261.50.find the percentage decrease in its price
FinnZ [79.3K]

The percent of change = ((new value - old value) / old value) × 100%

Our new value = $261.50

Our old value = $382

Plug our values into the equation above.

(($261.50 - $382) / $382) × 100% = -31.54%

8 0
3 years ago
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Can someone help me? I’ll reward points + brainalist
posledela

Step-by-step explanation:

THE ANSWER IS C. 31 INCHES

5 0
2 years ago
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1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
2 years ago
Expand 4x(7x-11)<br> For maths <br> Help please
harina [27]

Answer:

28x^2-44x

Step-by-step explanation:

Use the distributive property.

4x * 7x = 28x^2

4x * (-11) = -44x

We will get 28x^2-44x

Hope this helps!

7 0
2 years ago
A survey of 76 commercial airline flights of under 2 hours resulted in a sample average late time for a flight of 2.55 minutes.
nika2105 [10]

Answer:

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

2.55+1.96\frac{12}{\sqrt{76}}=5.248    

Since the time can't be negative a good approximation for the confidence interval would be (0,5.248) minutes. The interval are tellling to us that at 95% of confidence the average late time is lower than 5.248 minutes.

7 0
3 years ago
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