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Flauer [41]
1 year ago
9

A scientist needs 10 liters of a 20% acid solution for an experiment, but she has only a 5% solution and a 40% solution. To the

nearest tenth of a liter, about how many liters of the
5% and the 40% solutions should she mix to get the solution she needs?
Mathematics
1 answer:
Yanka [14]1 year ago
5 0

The volume required for a 5% solution is 5.7 L, while a 40% solution requires 4.3 L for the experiment.

<h3>What is defined as the percentage?</h3>

A percentage is a fraction of a whole represented as a number ranging from 0 and 100.

  • In this question, you would like to make a 10 litre 20% solution by combining 5% and 40% concentrations.
  • This question should have multiple answers.
  • Supposing that total volume of the 5% and 40% solutions is 10 L (no solution wasted), you can calculate the volume of solution required.

The equation should be as follows:

If 'x' is the volume of a 40% solution, then the volume of a 5% solution is:

10 L = 40% solution volume + 5% solution volume

10 L = x + 5% volume of solution

10 L - x = 5% solution volume

The volume would then be calculated as follows:

(volume 20% × concentration 20%) = (volume 40% × concentration 40%)           + (volume 5% × concentration 5%)

10 litre × 20% = x litre × 40% + (10- x) litre × 5%

10 L ×  20% = x litre  × 35% + 10 litre × 5%

x litre × 35 = 10 L × 20 - 10 L × 5

                 = 10 L × 15

x litre = 10 L × 15/35

x litre = 4.28 L

x litre = 4.3 L

40% solution volume = 4.3 L

The volume of 5% solution is equal to 10 L - 4.3 L = 5.7 L.

Thus, the volume of 5% solution  requires is 5.7 L and volume of 40% solution required is 4.3 L.

To know more about percentage, here

brainly.com/question/24304697

#SPJ9

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