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liubo4ka [24]
1 year ago
5

A runner completed a 26.2-mile marathon in 210 minutes.

Mathematics
2 answers:
Phoenix [80]1 year ago
8 0

Answer:

0.123 miles per min

8 mins per mile

The runner is talking about part (b)

Part a) is miles per minute and the runner said they did 10 minutes every mile same thing as minutes per mile or part b

Step-by-step explanation:

Since your doing per minute you do you do the amount of miles over the amount of minutes so you can see how many miles the runner went in each minute

And when doing per mile its the same idea you just minutes over miles now so you get for every mile the number of minutes.

bekas [8.4K]1 year ago
3 0

Answer: this is not a answer I don’t understand

Step-by-step explanation:

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Evaluate the expression 2(2x-3y)-5xy where x=-2 and y=-1
icang [17]

Answer:

-12

Step-by-step explanation:

2 (2x-3y)-5xy

4x-6y-5xy

4(-2)-6(-1)-5*-2*-1

-8+6-10

-12

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3 years ago
Brainliest if correct
Naddik [55]

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v = 176

Step-by-step explanation:

Since a fraction is essentially the same thing as dividing one number by another, we can multiply 44 by 4, the denominator of the fraction we are finding the numerator for, and get 176. This fraction is already in negative form, so we don't need to do anything else.

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3 years ago
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Under certain conditions the pressure of a
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Step-by-step explanation:

4 0
3 years ago
Ben wants to have his birthday at the biwking alley with a few of his friends, but he can spend no more that $80. The bowling ch
artcher [175]

Answer:

5.50p+45\leq 80\\\\p\leq 6.36\\\\\Rightarrow p\leq 6

Step-by-step explanation:

Ben\ invited\ p\ peoples\\\\

Charges of birthday party:

Flat\ fees=\$ 45\\\\Per\ person\ charges=\$ 5.50\\\\Charges\ for\ p\ people=p\times per\ person\ charges\\\\Charges\ for\ p\ people=p\times 5.50\\\\Charges\ for\ p\ people=5.50p\\\\Total\ charges\ for\ party=flat\ fee+charges\ for\ p\ person\\\\Total\ charges\ for\ party=45+5.50p

Ben\ has\ money=\$ 80\\\\Ben\ can\ not\ spend\ more\ than\ that.\\\\\Rightarrow Party\ charges\ for\ p\ peoples\leq 80\\\\5.50p+45\leq 80\\\\5.50p+45-45\leq 80-45\ \ \ \ \ \ \ \ \ subtract\ 45\ from\ both\ sides\\\\5.50p\leq  35\\\\p\leq \frac{35}{5.5}\\\\p\leq 6.36\approx 6\\\\p\leq  6

5 0
4 years ago
A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
3 years ago
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