It's easy! Please help me!

Mathematics

2 answers:

Makovka662 [10]2 years ago

8 0

You didn’t put the question, but if you repost I’d be happy to help you!

const2013 [10]2 years ago

4 0

Answer:

Sorry, but you did not put an attachment on there. please try again.

Step-by-step explanation:

Proving to you guys that I am HONEST:

I have had a sibling who was honest, so I definitely know how to be honest. He constantly lied all the time, and that's how he ended up not living with us anymore. The word "HONEST" means to be free of deceit and untruthfulness; sincere. So I am honest because I do NOT spend my time lying but instead achieving my goals by telling the truth. If I were to spend my time lying my life would be miserable and I would not have a good reputation. I have a good reputation as you can see. I used to have another Brainly account, but somebody hacked into it and deleted it (I am telling you the truth). If you would have seen my other account I had more than 500 friends in just two months, which is because I did not lie, but told the truth and made relationships with other people. You see you do have to be honest. For if I were asked if I had a boyfriend, I could simply say “yes” (in this case NO) or I could simply say “I would prefer to not talk about it at this moment.” You must see that that second answer is NOT a lie. So My answer would have to be I am HONEST! (Is being honest a bad thing?)

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The graph of y=ax+b, where a≠0, is always a line:

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Consider the decreasing case.

The line is above the x-axis, that is positive but decreasing. At 1 single point it cuts the x-axis, so x=0, and then it continues decreasing below the x-axis.

Back to our problem:

The graph of y=-1/2 x +2 is a decreasing line.,

so it CANNOT be
"positive over the interval (4, infinity) and negative over the interval (-infinity, 4)"

it is

"<span>negative over the interval (4, infinity) and positive over the interval (-infinity, 4)</span>"

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when x=4, the line cuts the x-axis.

check the graph of the line generated using desmos.com

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