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1 year ago

The distribution function of the univariate random variable x is continuous at x if and only if p(x

1 answer:

7 0

The distribution function of the univariate random variable x is continuous at x if and only if , F (x) = P (X ≤ x)

Continuous univariate statistical distributions are functions that describe the likelihood that a random variable, say, X, falls within a given range. Let P (a Xb) represent the probability that X falls within the range [a, b].

A numerically valued variable is said to be continuous if, in any unit of measurement, whenever it can take on the values a and b. If the random variable X can assume an infinite and uncountable set of values, it is said to be a continuous random variable.

If X can take any specific value on the real line, the probability of any specific value is effectively zero (because we'd have a=b, which means no range). As a result, continuous probability distributions are frequently described in terms of their cumulative distribution function, F(x).

To learn more about univariated data

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Jason accidentally locked himself out of his apartment, but remembered that he left a window open. The window is 8 feet above th

dalvyx [7]

Answer:

I Think Its 14 Feet.

Step-by-step explanation:

14 feet because the window is 8 feet high and he has to move it back 6 feet. So when you add 8 and 4 you would get the answer of 14 feet.

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3 years ago

Read 2 more answers

jane paid $40 for an item after she received a 20% discount. janes friend says this means that the original price of the item is

olga55 [171]

48x0.2= $9.6
$48-9.6=$38.40 Her friend is incorrect.
40/48 =0.83 or about 83% So, in this case she only got 17% off. :)
Hope I helped

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3 years ago

Please help!

tensa zangetsu [6.8K]

If the parabola has y = -4 at both x = 2 and x = 3, then since a parabola is symmetric, its axis of symmetry must be between x = 2 and x = 3, or at x = 5/2. Our general equation can then be:
y = a(x - 5/2)^2 + k
Substitute (1, -2): -2 = a(-3/2)^2 + k
-2 = 9a/4 + k
Substitute (2, -4): -4 = a(-1/2)^2 + k
-4 = a/4 + k
Subtracting: 2 = 2a, so a = 1. Substituting back gives k = -17/4.
So the equation is y = (x - 5/2)^2 - 17/4
Expanding: y = x^2 - 5x + 25/4 - 17/4
y = x^2 - 5x + 2 (This is the standard form.)

5 0

3 years ago

What is the product in simplest form? −8/9⋅5/6

Sedaia [141]

The answer is 20/27. 8/9x5/6=20/27.

4 0

3 years ago

Fill in Sin, Cos, and tan ratio for angle x. Sin X = 4/5 (28/35 simplified)

Fantom [35]

Answer:

Given: $\sin(x) = (4/5)$ .

Assuming that $0 < x < 90^{\circ}$ , $\cos(x) = (3/5)$ while $\tan(x) = (4/3)$ .

Step-by-step explanation:

By the Pythagorean identity $\sin^{2}(x) + \cos^{2}(x) = 1$ .

Assuming that $0 < x < 90^{\circ}$ , $0 < \cos(x) < 1$ .

Rearrange the Pythagorean identity to find an expression for $\cos(x)$ .

$\cos^{2}(x) = 1 - \sin^{2}(x)$ .

Given that $0 < \cos(x) < 1$ :

$\begin{aligned} &\cos(x) \\ &= \sqrt{1 - \sin^{2}(x)} \\ &= \sqrt{1 - \left(\frac{4}{5}\right)^{2}} \\ &= \sqrt{1 - \frac{16}{25}} \\ &= \frac{3}{5}\end{aligned}$ .

Hence, $\tan(x)$ would be:

$\begin{aligned}& \tan(x) \\ &= \frac{\sin(x)}{\cos(x)} \\ &= \frac{(4/5)}{(3/5)} \\ &= \frac{4}{3}\end{aligned}$ .

7 0

2 years ago