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irakobra [83]
1 year ago
14

Evaluate the expression, when x = 2 and y = 4.X + y + 3(x + 2y)Оа28Ob32Ос36Od30

Mathematics
1 answer:
kotegsom [21]1 year ago
3 0

C)36

1)Since X=2 and y=4, in order to evaluate it. Let's plug it in those values.

But firstly, we need to apply the Distributive Property.

x+y+3(x+2y)

x+y+3x+6y

2) Now let's add the similar terms

x+3x +6y+y

4x+7y

3) Plugging in

4(2)+7(4)

8+28

36

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Answer:

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Step-by-step explanation:

Hi there!

So, to answer this problem, I'll use the reverse method.

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The closest factor of 5 to 27 is 25.

5 can go in to 27,  5 times.

Continuing on, there is a 2 left over, so the answer to your question is

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Read 2 more answers
Select the correct answer.
Marta_Voda [28]

Answer:  Step 5

===================================================

Reason:

The order of operations is PEMDAS

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The multiplication and division are on the same level of precedent, and the same goes for addition and subtraction. Some math textbooks may refer to PEMDAS as BODMAS, which is basically the same thing.

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This is what steps 4 and onward should look like

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So that's why the error is in <u>step 5</u>

If there was parenthesis around the "2+10", and we had (2+10) \div 2, then step 5 given by your teacher would be correct.

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Step-by-step explanation:

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