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Ne4ueva [31]
4 years ago
9

Wesley and Mia deposit $800.00 into a savings account which earns 15% interest compounded annually. They want to use the money i

n the account to go on a trip in 2 years. How much will they be able to spend?
where A is the balance (final amount), P is the principal (starting amount), r is the interest rate expressed as a decimal, n is the number of times per year that the interest is compounded, and t is the time in years.
Round your answer to the nearest cent.
Mathematics
1 answer:
irga5000 [103]4 years ago
4 0

Answer:

1,058

Step-by-step explanation:

Interest= 800(.15)= 120 1 yr interest

A= 800 + 120= 920 on the 1st year

920 (.15)= 138 int. on the 2nd year

Therefore, 920+ 138= 1,058 final amount after 2 yrs.

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What is the result of 5 divided by one-fifth? 5 fraction bars. Each bar is labeled 1 with 5 boxes labeled one-fifth underneath.
FromTheMoon [43]

Answer:

25

Step-by-step explanation:

6 0
3 years ago
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Kirks family drove 36 miles in 50 minutes, which was 48% of the distance to his grandmothers house
krok68 [10]
Wait a sec while i answer this.
to find out the total... you would divide 36 by 48 and then times it by 100 which would equal 75 miles
8 0
3 years ago
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If a pair of regular dice are tossed once, use the expectation formula to determine the expected sum of the numbers on the upwar
Darya [45]

Answer:

The expected sum of the numbers on the upward faces of the two dice is 7.

Step-by-step explanation:

Consider the provided information.

If two pair of dice tossed the possible out comes are:

(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6)

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),  (5,6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5),  (6,6)

Now we need to find the expected sum of the numbers on the upward faces of the two dice.

The expected sums can be:

Sum:    2,      3,       4,       5,      6,      7,       8,        9,      10,    11,      12

Prob: 1/36, 2/36, 3/36, 4/36, 5/36, 6/36, 5/36, 4/36, 3/36, 2/36, 1/36

As we know that the expectation of experiment can be calculated as:

P(S_1)\cdot S_1+P(S_2)\cdot S_2+........+P(S_n)\cdot S_n

Here S represents the numerical outcomes and P(S) is the respective probability.

Substitute the respective values in the above formula.

=2\times\frac{1}{36}+3\times\frac{2}{36}+4\times\frac{3}{36}+5\times\frac{4}{36}+6\times\frac{5}{36}+7\times\frac{6}{36}+8\times\frac{5}{36}+9\times\frac{4}{36}+10\times\frac{3}{36}+11\times\frac{2}{36}+12\times\frac{1}{36}\\=\frac{252}{36}\\=7

Hence, the expected sum of the numbers on the upward faces of the two dice is 7.

8 0
4 years ago
The mass is 500 grams and the volume is 40 cubic centimeters.
Paha777 [63]

Answer: is there a question for/to the numbers gjven

4 0
3 years ago
The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while
Alex73 [517]

Answer:

286 students attended

148 non students attended

Step-by-step explanation:

Given

Tickets = 434

Students = \$4.00

Non-Students = \$6.00

Total = \$2032.00

Solving (a): Number of students

Represent students with S and non students with N

So:

S + N = 434 --- (1)

4S + 6N = 2032 --- (2)

Make N the subject of formula in (1)

N = 434 - S

Substitute 434 - S for N in (2)

4S +6(434 - S) = 2032

Open Bracket

4S + 2604 - 6S = 2032

Collect Like Terms

4S - 6S = 2032 - 2604

-2S = -572

Divide through by -2

S = 286

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

N = 434 - S

N = 434 - 286

N = 148

<em>148 non students attended</em>

4 0
3 years ago
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