Answer:
The liters that the tank will contain at 5:11 PM that day are:
Step-by-step explanation:
Firstly, you must identify the outlet flow of the water pumped from the tank, for this, you must subtract the last volume given from the first volume:
- 19,140 L - 8,097 L = 11,043 L
And the minutes that passed from the first volume until the last volume given (18 minutes from 4:47 PM to 5:05 PM), so, you must divide that two values to obtain the outlet flow:
- Outlet flow =
- Outlet flow =
- Outlet flow = 613.5

Now, you must see the next hour given (5:11 PM), if you see, from 5:05 PM to 5:11 PM has passed 6 minutes, taking into account this, you replace the equation of outlet flow to clear the volume:
- Outlet flow =
- Volume = Outlet flow * time
And replace the values to obtain the new volume pumped:
- Volume = 613.5
* 6 min - Volume = 3681 L.
At last, you must subtract these liters from the last volume identified in the tank:
- New Volume in the tank = 8097 L - 3681 L
- New Volume in the tank = 4416 L
The volume in the tank at 5:11 PM is <u>4416 Liters</u>.
<span>6x-2y=-8
-2y =-6x-8
y = 3x+4
y= 3x+4</span>
Yes, since adding two like variables will always result in the same variable.(i.e. x+x=2x not x^2). Any expression with the highest variable being to the power of 1 (or just x) is ALWAYS a linear expression.
<span>122.40 is the answer. I hope this helps :) Please give me a rate and Thanks :)</span>
325
Step-by-step explanation:
<h3>(x+8)2+(y+12)2=235</h3>