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Anarel [89]
3 years ago
14

Select the correct answer from each drop-down menu.

Mathematics
1 answer:
Harman [31]3 years ago
4 0

Answer:

AB = DF (Proved below)

Step-by-step explanation:

Here,

CE = CD + DE [since D is a point over CE]

= DE + EF [ Since, CD = EF (given)]

= DF  [ Since, E is a point over DF] ---------------(1)

Again,

AB  = CE (given) ------------------------(2)

So from (1) and (2),

AB = CE = DF

⇒ AB = DF (Proved)

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How do you find the probability? give me details please and answer my question step by step.
mart [117]

Answer:

to find theoretical probability, devide the favorable outcomes by the total possible outcomes

to find experimental probability, for example on a coin, devide how many times it landed on heads by how many times you flipped it

i hope this helps :)

8 0
4 years ago
A person starts driving and travels 3 km east to a store. The person then turns around and travels 1 km west to another store. F
hodyreva [135]
4km west. 3-1=2 then 2+2=4 km west
8 0
3 years ago
Improper fracations​
NemiM [27]

Answer:

64+77=141

Step-by-step explanation:

The whole number times the denominator plus the numerator. Then, add and do the same thing again with the other number and you get 64 and 77 then add and you get 141

5 0
3 years ago
Can someone tell me what it is and explain it in an easy way, I'm kind of an idiot
lubasha [3.4K]
1/2 x 3/4
1 x 3 / 2 x 4
= 3/8
6 0
3 years ago
Thetime(inhours)requiredtorepairamachineis an exponentially distributed random variable with parameter λ = 1 . What is 2 (a) the
mihalych1998 [28]

Answer:

a) 0.1353

b) 0.3679

Step-by-step explanation:

Let's start by defining the random variable T.

T : ''The time (in hours) required to repair a machine''

T ~ exp (λ)

T ~ exp (1)

The probability density function for the exponential distribution is

(In the equation I replaced λ = L)

f(x)=Le^{-Lx}

With L > 0 and x ≥ 0

In this exercise λ = 1 ⇒

f(x)=e^{-x}

For a)

P(T>2)

P(T>2)=1-P(T\leq 2)

P(T>2)=1-\int\limits^2_0 {e^{-x} } \, dx

P(T>2)=1-(-e^{-2}+1)

P(T>2)=e^{-2}=0.1353

For b)

P(T\geq 10/T>9)

The event (T ≥ 10 / T > 9) is equivalent to the event T ≥ 1 so they have the same probability of occur

P(T\geq 10/T>9)=P(T\geq 1)

P(T\geq 1)=1-P(T

P(T\geq 1)=1-(-e^{-1}+1)=e^{-1}=0.3679

4 0
3 years ago
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