Select the correct answer from each drop-down menu.

Mathematics

1 answer:

Harman [31]3 years ago

4 0

Answer:

AB = DF (Proved below)

Step-by-step explanation:

Here,

CE = CD + DE [since D is a point over CE]

= DE + EF [ Since, CD = EF (given)]

= DF [ Since, E is a point over DF] ---------------(1)

Again,

AB = CE (given) ------------------------(2)

So from (1) and (2),

AB = CE = DF

⇒ AB = DF (Proved)

You might be interested in

Please help! The distance a car travels, d, is proportional to a constant rate of speed, r, at different times, t.

Afina-wow [57]

There's a saying to this kind of equation: Rate + Time = Distance and B best fits the saying, so B must be right (Don't quote me on that, it may be wrong)

5 0

3 years ago

Determine whether each expression represents the statement divide the sum 15 and 6 by the difference of 10 and 3.

iris [78.8K]

Answer:

$\frac{15+6}{10-3}$

Step-by-step explanation:

Sum of 15 and 6 = 15 + 6

Difference of 10 and 3 = 10 - 3

So, the expression is

$\frac {15 + 6}{10-3}$

This is the required expression.

4 0

3 years ago

A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China. Find the length and width of a si

dusya [7]

The length and width of the similar rectangular screen are 110 meters and 35 meters respectively.

<u>SOLUTION: </u>

Given, A huge suspended LED screen is the centerpiece of The Place, a popular mall in Beijing, China.

We have to find the length and width of a similar rectangular screen

We are also given that the length is 5 meters more than 3 times its width,

Let width of rectangle be "b" meters, the its length will be 5 + 3b meters

And, the viewable area is 3,850 square meters.

$\begin{array}{l}{\text { So, area }=3850} \\\\ {\text { Length } \times \text { width }=3850} \\\\ {(5+3 b) \times b=3850} \\\\ {5 b+3 b^{2}=3850} \\\\ {3 b^{2}+5 b-3850=0}\end{array}$

Now,let us use quadratic formula:

$\begin{array}{l}{\mathrm{x}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}} \\\\ {\text { Then, } \mathrm{b}=\frac{-5 \pm \sqrt{5^{2}-4 \times 3 \times(-3850)}}{2 \times 3}}\end{array}$

$\begin{array}{l}{\mathrm{b}=\frac{-5 \pm \sqrt{25+46200}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm \sqrt{46225}}{6}} \\\\ {\mathrm{b}=\frac{-5 \pm 215}{6}} \\\\ {\mathrm{b}=\frac{-5+215}{6} \text { or } \frac{-5-215}{6}} \\\\ {\mathrm{b}=\frac{210}{6} \mathrm{or} \frac{-220}{6}}\end{array}$