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1 year ago

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Consider the following curve.f(x) = V x2 + 6x – XDetermine the domain of the curve. (Enter your ans(No Response)Find the interce

pts. (Enter your answers as comma-y-intercept (No Response)x-intercept (No Response)

1 answer:

tigry1 [53]1 year ago

4 0

Given the function:

$f(x)=\sqrt[]{x^2+6x}-x$

the graph of the function will be as follows:

As shown in the figure:

The domain is the values of x which can be f(x) is valid

As the function contain a square root, so, the root must be greater than or equal to zero

so, the domain will be:

$(-\infty,-6\rbrack\cup\lbrack0,\infty)$

The Y-intercept is the value of y which make x = 0

So, as shown: y-intercept = 0

The x-intercept is the value of x which make y = 0

So, as shown: x-intercept = 0

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3 years ago

The midpoint of segment AB is (1, 4). The coordinates of point A are (-2, -3). Find the coordinates of point B.

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The midpoint (-2,4) is up and to the left from (6,-1).
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3 years ago

Fill in the blanks. <br><br> sedrftgyuhihkgfndt7y

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3 years ago

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AREA, PERMITER AND VOLUME QUESTIONS.

castortr0y [4]

Answer:

Step-by-step explanation:

(A) The radius of the circle is=1.8m

Then diameter will be: 2r= $2{\times}1.8=3.6 m$

Circumference of circle= ${\pi}d$ = $3.14{\times}3.6=11.304 m$

Area of the circle= ${\pi}r^{2}=3.14{\times}(1.8)^{2}=10.17 m^{2}$

(B) The area of the rectangular backboard of basketball court = 18900 $cm^{2}$

Width=180cm

Area of rectangle= l{\times}b[/tex]

18900=l{\times}180[/tex]

$l=105 cm=1.05m$

Perimeter of the seating space=2(l+b)

= $2(32.5+18.4)$

= $101.8 m$

Perimeter of the basketball court=2(l+b)

= $2(15+28)$

= $86 m$

Now, total perimeter= perimeter of the basketball court+perimeter of the seating space.

Total perimeter= $101.8+86=187.8 m$

Area of the seating space= $l{\times}b$

= $32.5{\times}18.4=598 m^{2}$

(C) The shape consists of one square and 4 triangles, therefore area of square= $(side)^{2}=(3)^{2}=9 m^{2}$

Area of 4 triangles= $4{\times}(\frac{1}{2}{\times}B{\times}H)$

= $4{\times}(\frac{1}{2}{\times}3{\times}2)=12m^{2}$

Area of the shape= Area of the square+ area of the 4 triangles

= $9+12=21m^{2}$

(D) Perimeter of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by: $2(l+b)=2(40+10)=100 m$

Perimeter of rectangle with length 68 m and breadth=33 m is given by: $2(l+b)=2(68+33)=202 m$

Perimeter of the semicircle= $\frac{{\pi}d}{2}=\frac{3.14{\times}34}{2}=53.38 m$

Total perimeter= $100+201+53.38=355.38 m$

Area of rectangle with length=40 m (After converting cm to m) and breadth= 10 m is given by: $l{\times}b=40{\times}10=400 m^{2}$

Area of rectangle with length 68 m and breadth=33 m is given by: $l{\times}b=68{\times}33=2244 m^{2}$

Area of the semi circle= $\frac{{\pi}r^{2}}{2}=\frac{3.14{\times}17^{2}}{2}=453.73 m^{2}$

Total area= $400+2244+453.73=3097.73 m^{2}$

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3 years ago

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What is greater than 1.45? A. 0.009 B. 0.019 C. 0.0032 D. 0.0177

8_murik_8 [283]

Answer:

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3 years ago

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