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Rasek [7]
3 years ago
8

What is the equation that passes through (4, 3) and (2, -1)?

Mathematics
2 answers:
MrMuchimi3 years ago
5 0

<u>Answer:</u>

y = 2x - 5

<u>Step-by-step explanation:</u>

We are to find the equation of line the line which passes through the points (4, 3) and (2, -1).

Finding the slope:

Slope = \frac{3-(-1)}{4-2} =2

Substituting the coordinates of one of the given points and slope in the standard form of an equation to find the y intercept.

y=mx+c

-1 = 2 (2) + c \\\\ c = - 5

So the equation of the line would be y=2x-5

Georgia [21]3 years ago
4 0

Answer: first option.

Step-by-step explanation:

The equation of the line in Slope-Intercept form is:

y=mx+b

Where "m" is the slope of the line and "b" is the y-intercept.

To find "m", we need to substitute the coordinates of the points  (4, 3) and (2, -1) into this formula:

 m=\frac{y_2-y_1}{x_2-x_1}

We can identify that:

y_2=-1\\y_1=3\\x_2=2\\x_1=4

Then:

m=\frac{-1-3}{2-4}\\\\m=2

To find "b" we must substitute the slope and one of the given points into y=mx+b and solve for "b". Then, this is:

3=2(4)+b\\\\3-8=b\\\\b=-5

Therefore, the equation of this line is:

y=2x-5

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