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Bad White [126]
1 year ago
14

There are 10 girls and 6 boys in a class. The teacher randomly draws one student's name and then draws another. What is the prob

ability that the first name drawn will be a boy and the second will be a girl?
60%

23. 4%

16%

25%
Mathematics
1 answer:
marshall27 [118]1 year ago
4 0

The Probability of name drawn will be a boy is 3/8 ways and the girl will be 5/8 ways.

Given that,

In a class, there are 10 girls and 6 boys. After selecting one kid at random, the teacher selects another.

We have to find what probability is it that a boy will be the first name picked and a girl will be the second.

We know that,

Probability is number of favorable outcomes by total number of outcomes.

Total number of outcomes is 16.

For boys the number of favorable outcome is 6

For girls the number of favorable outcome is 10.

For selecting boy is

Probability is 6/16=3/8

For selecting girl is

Probability is 10/16=5/8

Therefore, The Probability of name drawn will be a boy is 3/8 ways and the girl will be 5/8 ways.

To learn more about probability visit: brainly.com/question/11234923

#SPJ4

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Express the null hypothesis and the alternative hypothesis in symbolic form. Use the correct symbol ( μ, rho, σ) for the indicat
ipn [44]

Answer:

c) H0 : p = 5.8%

H1 : p > 5.8%

Step-by-step explanation:

At the null hypothesis, we test that the percentage is equal to a certain value. At the alternate hypothesis, we have a test about this percentage, if it is more, less, or different from the tested value.

A psychologist claims that more than 5.8 percent of the population suffers from professional problems due to extreme shyness

At the null hypothesis, we test if the percentage is 5.8%

H_0: p = 5.8\%

At the alternate hypothesis, we test if this percentage is more than 5.8%. So

H_a: p > 5.8\%

This means that the correct answer is given by option c.

3 0
2 years ago
Read 2 more answers
What substitution should be used to rewrite 4x^4-21x^2+20 =0 as a quadratic equation
marysya [2.9K]

I would substitute y = x^2

4y^2 -21y+20=0

7 0
3 years ago
Mickey keeps picking playing cards out of a standard deck of 52 cards, hoping that she will
andrew-mc [135]

Answer:

03%

Step-by-step explanation:

In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.

Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)

Now, there are 13 diamonds and 39 other cards. Hence,

P(A)=(\frac{39}{52})⁷=0.1335

After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,

P(B)=\frac{13}{52}=0.25

Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)

Therefore probability that Mickey will draw her first diamond on the 8th

attempt is 3%

7 0
3 years ago
What's the difference?<br> -1 1/8 - 6/8=
sergejj [24]

Answer: -3/8

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
3 years ago
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