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max2010maxim [7]
3 years ago
5

I need help on this I will give brainlist help it will mean a lot this is my last math problem help me!​

Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

Store Z has the best sale price of $28

Step-by-step explanation:

Starting Price = $35

Store X offers 15% off = only 5.25$ off (0.15 * 35 = 5.25, 35 - 5.25 = 29.75) Final Price = $29.75

Store Y offers $5 off = only 5$ off (35 - 5 = 30) Finaly Price = $30

Store Z offers 1/5 off = only 7$ off (1/5 = 0.20, 0.20 * 35 = 7, 35 - 7 = 28) Final Price = $28 (BEST PRICE)

Natalka [10]3 years ago
5 0

Answer:

the second one

Step-by-step explanation:

i did it in my head and double checked :)

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So we are given that the line is parallel to the given line, meaning that they both have the same slope. The slope of the line we can then tell by just looking at the equation. It is the coefficient of x (since this is already in slope-intercept form) and that is 1/2.

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Find the critical numbers and the intervals on which the function f(x)=9x5−3x3+6f(x)=9x5−3x3+6 is increasing or decreasing. Use
Ierofanga [76]

Answer:

x = (0, -√(3/5), √(3/5)) are the critical points.

Local maximum at √(3/5), and local minimum is at -√(3/5).

The function is increasing in the interval

(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

Step-by-step explanation:

Given the function

f(x) = 9x^5 - 3x³ + 6

First of all, take the first derivative of this, to have

f'(x) = 45x^4 - 27x²

The critical point are the points where the first derivative vanishes, that is

f'(x) = 0

Now, solve the equation

45x^4 - 27x² = 0

9x²(5x² - 3) = 0

x = 0 twice

Or

5x² - 3 = 0

5x² = 3

x² = 3/5

x = ±√(3/5)

So, x = (0, -√(3/5), √(3/5)) are the critical points.

Local maximum is when f'(x) > 0, this is √(3/5) in this case,

and local minimum is when f'(x) < 0, this is -√(3/5) in this case.

Now, we need to test for the various intervals to determine where the function increases and decreases.

(−∞, -√(3/5)):

f'(-√(4/5)) = 45(-√(4/5))^4 - 27(-√(4/5))²

= 36/5 > 0. Increasing

(-√(3/5), 0):

f'(-√(2/5)) = 45(-√(2/5))^4 - 9(-√(2/5))²

= -18/5 < 0. Decreasing

(0, √(3/5)):

f'(√(1/5)) = 45(√(1/5))^4 - 9(√(1/5))² = -18/5 < 0. Decreasing

(√(3/5), ∞): f'(1) = 45(1)^4 - 9(1)² =

36 > 0. Increasing.

Therefore, the function is increasing in the interval

(−∞, -√(3/5)) U (√(3/5), ∞)

And decreasing in the interval

(-√(3/5), 0) U (0, √(3/5))

6 0
3 years ago
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