1 dime is required to make $1.02 cents using 9 coins collections
<h3>How to solve</h3>
<u>Given data</u>
9 coins
a collection of pennies, nickels, dimes, and quarters
total of $1.02 with at least one coin of each type
solution
$1.02 = 102cents
1 penny = 1 cent
1 nickel = 5 cents
1 dime = 10 cents
1 quarter = 25 cents
having one coin of each means 4 coins which is equal to:
1 + 5 + 10 + 25 = 41 cents (fulfilling the first condition remaining 5 coins)
102 - 41 = 61
balancing the remaining coins to make up 61, we first get a penny to reduce the amount 60 cents ( 4 coins remaining )
hence we have
2*25 +2*5 = 60 cents ( 2quarters 2 nickel)
in total we have
2 pennies + 3 nickels + 1 dime + 3 quarters = 9 coins
2 * 1 + 3 * 5 + 1 * 10 + 3 * 25 = 102 cents
Therefore 1 dime is required to make $1.02 cents using 9 coins collections
Read more on dimes here: brainly.com/question/435257
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