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Dmitry [639]
1 year ago
10

you have nine coins: a collection of pennies, nickels, dimes, and quarters having a total value of $1.02, with at least one coin

of each type. how many dimes must you have?
Mathematics
1 answer:
raketka [301]1 year ago
3 0

1 dime is required to make $1.02 cents using 9 coins collections

<h3>How to solve</h3>

<u>Given data</u>

9 coins

a collection of pennies, nickels, dimes, and quarters

total of $1.02 with at least one coin of each type

solution

$1.02 = 102cents

1 penny = 1 cent

1 nickel = 5 cents

1 dime = 10 cents

1 quarter = 25 cents

having one coin of each means 4 coins which is equal to:

1 + 5 + 10 + 25 = 41 cents (fulfilling the first condition remaining 5 coins)

102 - 41 = 61

balancing the remaining coins to make up 61, we first get a penny to reduce the amount 60 cents ( 4 coins remaining )

hence we have

2*25 +2*5 = 60 cents ( 2quarters 2 nickel)

in total we have

2 pennies + 3 nickels + 1 dime + 3 quarters = 9 coins

2 * 1 + 3 * 5  + 1 * 10 + 3 * 25 = 102 cents

Therefore 1 dime is required to make $1.02 cents using 9 coins collections

Read more on dimes here: brainly.com/question/435257

#SPJ1

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Using the rational root theorem, it is found that your friend is correct.

<h3>What is the rational root theorem?</h3>
  • It is a theorem that states that for a polynomial with integer coefficients, with q being the factors of the leading coefficient and p being the factors of the constant, every <u>possible rational root</u> is the format \frac{p}{q}.

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To learn more about the rational root theorem, you can take a look at brainly.com/question/10937559

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