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Gekata [30.6K]
3 years ago
13

Mrs. Diaz graded 24 tests in 0.5 hours. How many tests per hour did she grade?

Mathematics
1 answer:
nasty-shy [4]3 years ago
6 0
48 tests in a hour assuming she goes at the same rate
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The answer would be D
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3 years ago
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Describe the transformations of how the graph y=x^2 can be transformed into y= -1/5 (x-4)^2 + 2
Orlov [11]

Answer:

Reflected over the x-axis, vertically shrunk by a factor of 1/5, moved right 4 units and up 2 units.

Step-by-step explanation:

Parent Graph: f(x) = a(bx - h)² + k

<em>a </em>is vertical stretch (a > 1) or shrink (a < 1) and reflection over x-axis

<em>b</em> is horizontal stretch or shrink and reflection over y-axis

<em>h</em> is horizontal movement left (if positive) or right (if negative)

<em>k</em> is vertical movement up (if positive) or down (if negative)

Now that we have our rules, we simply apply it to y = -1/5(x - 4)² + 2

<em>a</em> = -1/5, so reflection over x-axis and vertical shrink of 1/5 (1/5 < 1)

Nothing has changed <em>b</em>, so no horizontal stretch/shrink

<em>h</em> = -4, so horizontal movement right 4 units

<em>k</em> = 2, so vertical movement up 2 units

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3 years ago
ASAP HELP PLZZZZ What is the image of the point (9, -2) after a rotation of o counter-clockwise about the origin?
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Answer:

It should be (2,9).

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Nora measured the angles of a triangle. Two of the angles measured 20° What was the measure of the third angle of Nora’s triangl
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Answer:

140°

Step-by-step explanation:

The sum of angle of a triangle is equal to 180°.

Two of the angles measured 20°.

We need to find the measure of the third angle of Nora’s triangle. let the third angle is x. So,

20+20+x = 180

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x = 180-40

x = 140°

So, the third angle of the triangle is 140°.

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3 years ago
A woman walks due west on the deck of a ship at 3 mi/h. The ship is moving north at a speed of 22 mi/h. Find the speed and direc
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Answer: The speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

Step-by-step explanation:

Since we have given that

Speed at which woman walks due west = 3 mi/hr

Speed at which ship moving due north = 22 mi/hr

Now it forms "Pythagorus theorem":

So, it becomes,

H^2=B^2+P^2\\\\H^2=3^2+22^2\\\\H^2=9+484\\\\H^2=493\\\\H=\sqrt{493}\\H=22.20\ mi/hr

And the direction of the woman relative to the surface of the water is given by

\theta=\sin^{-1}x(\dfrac{3}{22.2})=7.76\approx 8^\circ

Hence, the speed is 22.2 mi/hr and woman is 8° north relative to the surface of the water.

5 0
3 years ago
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