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Alekssandra [29.7K]
1 year ago
12

What is summation notation for the series? b. 500+490+480+ . . . . . . . +20+10

Mathematics
1 answer:
marin [14]1 year ago
7 0

The summation notation for the series 500+490+480+ . . . . . . . +20+10 is

25500-10\sum\limits^{50}_{n=1} {n}

A summation notation is used to express a long summation into a single notation.

The given series is:

    500+490+480+ . . . . . . . +20+10

This is an arithmetic series with:

a(1) = 500, and

d = 490 - 500 = -10

The last term is a(n) = 10. Find n first by using the nth term formula of an arithmetic sequence:

a(n) = a(1) + (n-1) . d

10 = 500 + (n-1) . (-10)

10 = 500 -10n + 10

10 n = 500

n = 50

Write the explicit formula for the nth term:

a(n) = a(1) + (n-1) . d

a(n) = 500 + (n-1) . (-10)

a(n) = 500 -10n + 10

a(n) = 510 - 10n

The series is the summation notation from n=1 to n = 50

=\sum\limits^{50}_{n=1} {a(n)}

=\sum\limits^{50}_{n=1} {(510-10n)}

=\sum\limits^{50}_{n=1} {510} -\sum\limits^{50}_{n=1} {10n}

=510\times50-10\sum\limits^{50}_{n=1} {n}

=25500-10\sum\limits^{50}_{n=1} {n}

Learn more about summation notation of a series here:

brainly.com/question/23742399

#SPJ4

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3 0
4 years ago
Numbers 11,12,13 and 14
leonid [27]

Answer:

11.  ×8; ×27; ÷8

12. ÷16; ÷256; ×16

13. ×8

14. ×4

Step-by-step explanation:

11. g(x) =5x³

g₁ = 5x₁³

g₂ = 5x₂³

g₂/g₁ = (x₂/x₁)³

a. x is doubled. g₂/g₁ = (2x₁/x₁)³ = 2³ = 8

If x is doubled, g is multiplied by eight.

b. If x is tripled, g₂/g₁ = (3x₁/x₁)³ = 3³ = 27

If x is tripled, g is multiplied by 27.

c. If x is halved, g₂/g₁ = (½x₁/x₁)³ = (½)³ = ⅛

If x is halved, g is divided by 8.

12. ƒ(x) = 3/x⁴

f₁ = 1/x₁⁴

f₂ = 1/x₂⁴

f₂/f₁ = (x₁/x₂)⁴

a. x is doubled. f₂/f₁ = (x₁/2x₁)⁴ = (½)⁴ = 1/16

If x is doubled, f is divided by 16.

b. If x is quadrupled, f₂/f₁ = (x₁/4x₁)⁴= (¼)⁴ = 1/256

If x is tripled, f is divided by 256.

c. If x is halved, f₂/f₁ = [x₁/(½x₁)]⁴ = 2⁴ = 16

If x is halved, f is multiplied by 16.

13. V = ⁴/₃πr³

V₁ = ⁴/₃πr₁³

V₂ = ⁴/₃πr₂³

V₂/V₁ = (r₂/r₁)³

r is doubled. V₂/V₁ = (2r₁/r₁)³ = 2³ = 8

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V₁ = πr₁²h

V₂ = πr₂²h

If r is doubled and h stays the same, V₂/V₁ = (2r₁/r₁)² = 2² = 4

The volume of the cylinder is quadrupled.

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