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Gnesinka [82]
1 year ago
10

A rectangle's perimeter is 216 m. Its length is 4 m longer than three times its width. Use an equation to find the rectangle's l

ength and width.
Mathematics
1 answer:
Anvisha [2.4K]1 year ago
8 0

w= 26.5 m

l = 87.5 m

1) Gathering the data

2p= 216

l = 3w +4

2) We can write the Perimeter as:

2P = 2(w+l) <em>Plug into that the equations above</em>

216 = 2(w +3w+4)

216 = 2(4w +4) <em>Distribute the factor</em>

216 = 8w +4

216-4 = 8w <em>Flip it</em>

8w = 212 <em>Divide both sides by 8</em>

w= 26.5

Since l = 3w +4

l = 3(26.5) +4

l= 87.5

3) So the width is 26.5 meters and the length is 87.5 meters long

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bearing in mind that standard form for a linear equation means

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Fraction of the shape shaded on these two shapes??
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3 years ago
Please solve with explanation.
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Answer:

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Perimeter = 55.31 cm

Step-by-step explanation:

Applying,

Area of the figure = area of the rectangle- area of the triangle

A = lw+bh/2............... Equation 1

From the question,

Given: l = 16 cm, w = 12 cm, h = 8cm, b = 8 cm

Substitute these values into equation 1

A = (16×12)-(8×8/2)

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Perimeter P = /BC/+/CD/+/DE/+/EF/+/FG/+/GA/

Applying pythagoras theorem to get /FG/

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Therefore,

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