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Korvikt [17]
4 years ago
5

Write a equation in standard form that contains a slope of 3 and contains (1,6)

Mathematics
1 answer:
jeka944 years ago
5 0

bearing in mind that standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{6}) ~\hspace{10em} \stackrel{slope}{m}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{6}=\stackrel{m}{3}(x-\stackrel{x_1}{1})\implies y - 6 = 3x-3 \\\\\\ y=3x+3\implies -3x+y=3\implies \stackrel{\textit{standard form}}{3x-y=-3}

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4x-7x=13 in a fraction
Naddika [18.5K]
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4 years ago
Does anyone know the answer to this.
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Answer:

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Step-by-step explanation:

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tangare [24]
To fine the mean for a first add up all the players heights then divide by the number of players.

Mean=(198+199+200+201+202)÷5
=1000÷5
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The answer to a is 200

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201= (199+198+199+200+201+202+x) ÷ 6
201=1000+x ÷ 6
Then Im going to multiply 201 by 6 to get rid of the 6 on the other side.
1206=1000+x
Then I’m going to subtract 1000 from both sides to get x by itself
206=x

So the new players height is 206 .
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