What does this equal -5/6+(-5/6)=

Admission to the county fair costs $9 per person. The ride tickets cost $2.50 each.

maksim [4K]

Answer:$11.5

Step-by-step explanation:

Admission = $9 charged once

each ride = $2.5x (x=number of rides)

Total cost for x rides

=2.5x+9

7 0

2 years ago

A car traveled 180 miles at a constant rate. Write an equation that would

Mnenie [13.5K]

Answer:

180/t = r

Step-by-step explanation:

In this question, we would have to write an equation that represents the scenario given.

We know that the car traveled 180 miles at a constant rate.

We would use the y = mx + b format for the equation, but replacing the variables with "r" and "t"

We know that 180 will be our y-variable, since that would be the base of the equation:

180 = ???

And to find how long/fast it will take the car, we would need to multiply the rate of speed "r" and time "t" in order to get our distance.

Plug it into the equation:

180 = rt

With this set up, you can find the rate of speed of the car when you know the time.

You would simply solve it as:

180/t = r

7 0

3 years ago

in one particular suburb slacks have been reduced to $36. This price is at 90% of the original price for slacks. Given this what

frez [133]

$40
40*90/100 = 36
You just have to be careful with the rest of the problem

7 0

3 years ago

The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction

Len [333]

Answer:

(a) n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable X represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, μ = $16,642 and standard deviation is, σ = $2,400.

Assuming that the random variable X follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

For a sample size of n = 20

$P(\mu-200$

$=P(-0.37$

For a sample size of n = 50

$P(\mu-200$

$=P(-0.59$

For a sample size of n = 100

$P(\mu-200$

$=P(-0.83$

For a sample size of n = 500

$P(\mu-200$

$=P(-1.86$

n : 20 50 100 500

P (-200 < X - μ < 200) : 0.2886 0.4444 0.5954 0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample ( $\bar x$ ) approaches the whole population mean ( $\mu_{x}$ ).