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3 years ago

Find x no need for explanation I just need answer thanks

Mathematics

1 answer:

ikadub [295]3 years ago

3 0

Answer:

x = 12 m

Step-by-step explanation:

Length = x m

Width = 3⅔ = 11/3

Area = 44 m²

Area of rectangle = length × width

Plug in the values into the equation

$44 = x \times \frac{11}{3}$

$44 = \frac{11x}{3}$

Multiply both sides by 3

$44 \times 3 = \frac{11x}{3} \times 3$

$132 = 11x$

Divide both sides by 11

$12 = x$

x = 12

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We let x and y represent the two angles,

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4 years ago

Budget A student group has $8,000 budgeted for a field trip. The cost of transportation for the trip is $3,400. To stay within

inna [77]

Answer:

The answer is below

Step-by-step explanation:

Let the budget be represented by B. Since the grouo has only $8,000, hence, the inequality can be represented as:

B ≤ $8000

Also, $3400 was spent on transportation. If other cost is represented by C, therefore, other cost is given as:

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7 0

4 years ago

David leaves the house to go to school. He walks 200 meters west and

kvasek [131]

Pythagorean Theorem, where a^2+b^2=c^2. Just plugging in the numbers:
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3 0

3 years ago

If S is a compact subset of R and T is a closed subset of S, then T is compact. Prove this using the definition of compactness.

wlad13 [49]

Answer:

It has been proved that T is compact

Step-by-step explanation:

To prove this using the definition of compactness, let's assume that T is

not compact. Now, if that be the case, an open cover of T will exist. Let's call this open cover "A". Now, this open cover will have no finite subcover.

Now, from the question, since T is closed, it’s complement R\T will be open.

Therefore, if we add the set R\T to the collection of sets A, then we'll have an open cover of R and also of S.

Due to the fact that S is compact, this

cover will have a finite sub - cover which we will call B.

Finally, either B itself or B\{R\T} would be a finite sub - cover of A. This is a contradiction.

Thus, it proves that T has to be compact if S is to be a compact subset of R and T is to be a closed subset of S.

3 0

3 years ago