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myrzilka [38]
2 years ago
8

Find x no need for explanation I just need answer thanks

Mathematics
1 answer:
ikadub [295]2 years ago
3 0

Answer:

x = 12 m

Step-by-step explanation:

Length = x m

Width = 3⅔ = 11/3

Area = 44 m²

Area of rectangle = length × width

Plug in the values into the equation

44 = x \times \frac{11}{3}

44 = \frac{11x}{3}

Multiply both sides by 3

44 \times 3 = \frac{11x}{3} \times 3

132 = 11x

Divide both sides by 11

12 = x

x = 12

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What is the simplified from of 4x^2-25 over 2x-5?
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3 years ago
The ages of the Oscar-winners for best actor and actress for the years 1970 through 1990 are given below: Women: 34, 34,26,37,42
Artemon [7]

Answer:

See explanation below.

Step-by-step explanation:

Numerical way

We can calculate the mean and the standard deviation from a sample with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s= \frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

We have the following dataset for women: 34,34,26,37,42,41,35,31,41,33,30,74,33,49,38,61,21,41,26,80,72

And the mean and deviation are:

\bar X_F = 41.857

s_F = 16.399

We can calculate the median ordering the data like this:

21,26,26,30,31,33,33,34,34,35,37,38,41,41,41,42,49,61,72,74,80

And the median would be on the 11 position of the data ordered, for this case is:

median_F = 37

Minimum_F = 21 , Maximum_F = 80

And the range is given by: Range_F = 80-21=59

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{16.399}{41.857}=0.392

We have the following dataset for men:

43, 40,48,48,56,38,60,32,40,42,37,76,39,55,45,35,61,33,51,32,42

And the mean and deviation are:

\bar X_M = 45.381

s_M = 11.218

We can calculate the median ordering the data like this:

32, 32,33,35,37,38,39,40,40,42,42,43,45,48,48,51,55,56,60,61,76

And the median would be on the 11 position of the data ordered, for this case is:

median_M = 42

Minimum_M = 32 , Maximum_F = 76

And the range is given by: Range_M = 76-32=44

We can also calculate the coefficient of variation given by:

\hat{CV} =\frac{s}{\bar X} = \frac{11.218}{45.381}=0.247

We se that the mean for the male groups is higher than the mean for female group. The deviation is higher for the female group comapred to the male group. We have more variation for the female group as we can see on the range and the coeffcient of variation.

Graph

We can see the histograms for each group on the figures attached.

As we can see the histogram for males is skewed to the right with the median lower than the mean.

By the other hand the histogram for the female group seems to be skewed to the right also but with missing values on the interval 50-60, for this reason we have more variation compared to the male group.

7 0
3 years ago
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