The circle with center O has two chords AC and EF which are of same length 9.07.
OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.
The circle theorem states: congruent chords are equidistant from the center.
OD is congruent to OB.
Option A is the right answer.
1.) 24 pack for $6.88
2.) 12 oz box for $2.15
3.) 16 pound turkey for $20.00
4.) $1.60 per notebook
Answer:
blue
Step-by-step explanation:
its blue because the lesser the bigger please hope you get it right
73 is your answer do 73 time 3, 3*3=9 put the 9 down then 7*3=21 so the answer is 219 which is the number your dividing by. Always times your answer by the number smallest number and if it equals the biggest number in that problem that means your correct. So the answer is 73. Hope this helps.
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155

OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.