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babunello [35]
1 year ago
6

What is the solution to this system of linear equations 3x 2y 14 5x y 32

Mathematics
1 answer:
Leya [2.2K]1 year ago
6 0

After simplification, the solution of this system of linear equation is (3.85, 12.75).

In the given question we have to find the solution to this system of linear equations 3x-2y=14 or 5x+y=32.

The given system of linear equations is:

3x-2y=14.......................(1)

5x+y=32.......................(2)

Multiply equation 2 by 2, we get

10x+2y=64.......................(3)

Add equation 3 by 1, we get

10x+2y+3x-2y=64-14

13x=50

Divide by 13 on both side, we get

x=3.85

Now put the value of x in equation 2

5(3.85)+y=32

19.25+y=32

Subtract 19.25 on both side, we get

y=12.75

So, the solution of this system of equation is (3.85, 12.75).

To learn more about system of linear equation link is here

brainly.com/question/27664510

#SPJ4

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What is the value of 2/7 divided by 4/9
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Answer:9

Step-by-step explanation:

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15 POINTS!<br> What is the correct answer for Dean's problem? Explain where he went wrong.
prohojiy [21]

Answer:

The slope is 5/-2.

Step-by-step explanation:

Slope is y1-y2 over m1-m2 (rise over run). The first ordered pair is -2 (m1) and 11 (y1). We then subtract the second ordered pair (4 (m2) and -4 (y2)) from the first.

11 - (-4) = 11 + 4 = 15

-2 - 4 = -6

Remember, slope is rise over run (y over x), so the slope is 15/-6. Now, we must simplify. 15/-6 = 5/-2

Dean went wrong because he thought that slope was run over rise (x over y). If he had switched the two numbers, his answer would have been correct.

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The following data values represent a population. What is the variance of the values? 7, 5, 11, 1, 11
MaRussiya [10]
The mean is 35/5=7

The variance is the average of the sum of squared differences of each element from the mean:

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3 0
2 years ago
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Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and 1 red marbles. Find the following probabilities of Mirand
kvasek [131]

Answer:

(a)\frac{5}{7},\frac{1}{6} (b)\frac{1}{7},\frac{1}{6} (c)\frac{5}{7},\frac{2}{3},\frac{3}{5}

Step-by-step explanation:

GIVEN: Miranda has a bag of marbles with 5 blue marbles, 1 white marbles, and

TO FIND: a) A Blue, then a red Preview

,b)A red, then a white Preview

,c) A Blue, then a Blue, then a Blue.

SOLUTION:

Total marbles in bag =7

(a)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing red marble  =\frac{\text{total red marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(b)

Probability of drawing red marble =\frac{\text{total red marble}}{\text{total marbles}}

                                                          =\frac{1}{7}

As marble is not returned to bag,

Probability of drawing white marble  =\frac{\text{total white marble}}{\text{total marbles}}

                                                         =\frac{1}{6}

(c)

Probability of drawing blue marble =\frac{\text{total blue marble}}{\text{total marbles}}

                                                          =\frac{5}{7}

As marble is not returned to bag,

Probability of drawing second blue marble  =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                         =\frac{4}{6}=\frac{2}{3}

As marble is not returned to the bag

Probability of drawing third blue marble   =\frac{\text{total blue marble}}{\text{total marbles}}

                                                                    =\frac{3}{5}

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