Question

Three less than the quotient of ten and a number, increased by six” when n = 2?

Answer 1

Answer: The required value is 8.

Step-by-step explanation:

Since we have given that

three less than the quotient of ten and a number, increased by six”

Let the number be 'n'.

So, quotient of ten and a number is given by

$\dfrac{10}{n}$

Three less than the quotient is given by

$\dfrac{10}{n}-3$

Increased by 6 is given by

$\dfrac{10}{n}-3+6\\\\=\dfrac{10}{n}+3$

If n =2, we get that

$\dfrac{10}{2}+3\\\\=5+3\\\\=8$

Hence, the required value is 8.

Answer 2

(10/n  +6) -3
10/2+6-3
5+6-3
11-3
8
Hope this helped!