Answer:
f(x)=(2x-7)^7(x+3)^4
When y=0, (2x-7)^7=0 and x=3.5 OR
(x+3)^4=0, and x=-3
Look at x=h or f(2)
That is 96-56-44+2 and it is not equal to 0. (x-2) is not a factor.
x^3-5x^2+6x-30
after trying 1,2, and 3, I tried 5
5/1===-5===6===-30
==1===0====6====30
(x^2-6) with no remainder
the factors are (x-5)(x^2+6)
the zeroes are 5, +/- i sqrt (6). Only one real 0.
hope this helps let me know in the comments if i'm wrong
Answer:
h(x) = x/3 - 7
Step-by-step explanation:
Check the picture below, that's a parabolic graph of a quadratic equation with a negative leading coeffficient, like this one, the one in the graph is just for initial velocity, but, the highest point is at the vertex for any of these parabolas.
and this one is not exception, so where's the vertex? what's A or the y-coordinate when the vertex is reached?, well, let's check.

so, that's the vertex, and when the width is that much, the Area reaches a maximum of that much.
Answer:
i would help you but i dont see no picture