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goldfiish [28.3K]
1 year ago
14

16 - 5a +2a - 1 = 41 - a

Mathematics
2 answers:
Leya [2.2K]1 year ago
7 0

Answer:

a= -13

Step-by-step explanation:

mr Goodwill [35]1 year ago
3 0

Answer:

-13

Step-by-step explanation:

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Factor out the GCF from the terms of the polynomial-2x^5-6x^3-16x^2
elena-s [515]

Answer:

(-1x^3 - 3x - 8)(2x^2)

Step-by-step explanation:

Note how x^2 is a factor of all three terms of this polynomial.  Also, 2 is a factor of those three terms.  Thus, the GCF is 2x^2.

Dividing -2x^5-6x^3-16x^2 by 2x^2, we get:

(-1x^3 - 3x - 8)(2x^2) (the polynomial in factored form)

8 0
4 years ago
Please help me in this
iVinArrow [24]

Answer:c

Step-by-step explanation:

8 0
3 years ago
At a college campus, random drug tests are carried out to prevent use of prohibited drugs by athletes. Of all the athletes on ca
saw5 [17]

Answer:

a) 0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

b) 0.2693 = 26.93% probability that this drug user never used the prohibited drug.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

A. If an athlete is selected at random, what is the probability that athlete will test positive for prohibited drug use?

100 - 5 = 95% of 8%

100 - 13 = 87% of 17%

11% of 75%

So

p = 0.95*0.08 + 0.87*0.17 + 0.11*0.75 = 0.3064

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use.

B. If an athlete tests positive after a drug test, what is the probability that this drug user never used the prohibited drug?

Conditional Probability

Event A: Tests Positive

Event B: Never used the drug.

0.3064 = 30.64% probability that athlete will test positive for prohibited drug use

This means that P(A) = 0.3064

Probability of testing positive while never using the drug.

11% of 75%. So

P(A \cap B) = 0.11*0.75 = 0.0825

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0825}{0.3064} = 0.2693

0.2693 = 26.93% probability that this drug user never used the prohibited drug.

8 0
3 years ago
Find the area of the trapezoid
AleksandrR [38]

Answer:

112

Step-by-step explanation:

add both bases the multiply by the height

4 0
3 years ago
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The richardson family is out to dinner at their favorite restaurant. The bill comes to $32.00. How much money should they leave
goldfiish [28.3K]
$36.40
$32 for the bill an $6.40 for the 20% tip

8 0
4 years ago
Read 2 more answers
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