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Helga [31]
4 years ago
12

A line passes through the point (–2, 7) and has a slope of –5. mc009-1.jpg What is the value of a if the point (a, 2) is also on

the line?

Mathematics
2 answers:
Law Incorporation [45]4 years ago
8 0
This should help you.

RideAnS [48]4 years ago
6 0

The correct answer is -1


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HELPPPPPPPPPPPP PLSSSSSSSSSSSSSS
adoni [48]

Answer: it’s C

Step-by-step explanation:

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3 years ago
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Jules purchased a box of baseball cards for her collection. The original price was $22.80, but the store was having a sale with
Nesterboy [21]
With the discount the cards cost $17. 10
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3 years ago
HELP, i’m not the best in math... will give brinley. SHOW WORK.<br><br> 3x^2-5x+5y-4+12x
riadik2000 [5.3K]

Answer:

 simplified: 3x^2+7x+5y-4

Step-by-step explanation:

all you gotta do is you add -5x and 12x

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On average 20% of the gadgets produced by a factory are mildly defective. I buy a box of 100 gadgets. Assume this is a random sa
Softa [21]

Answer:

a) P(A)=P(x

b) P(A)\approx 0.085

Step-by-step explanation:

The proportion of defective gadgets for this factory is p=0.2.

If a sample of n=100 gadgets is taken from the production, we can model the amount of defectives gadgets in this sample as a binomial random variable.

The probability of having k defectives in the sample can be written as:

P(x=k)=\binom{100}{k}p^k(1-p)^{100-k}

Then, we can write the expression to calculate the probabilities of A: "less than 15 gadgets are mildly defective":

P(A)=P(x

If we approximate this binomial distribtution to a normal distribution, we can calculate the new parameters as:

\mu=np=100*0.2=20\\\\\sigma=\sqrt{np(1-p)}=\sqrt{100*0.2*0.8}=\sqrt{16}=4

The continuity factor is applied for the change from a discrete distribution (binomial) to a continous distribution (normal). Then we have:

P(A)=P(X

Now, we can calculate the probability P(A):

z=(X-\mu)/\sigma=(14.5-20)/4=-5.5/4=-1.375\\\\P(A)=P(X

5 0
4 years ago
Help!!!!
shtirl [24]

Answer:

82.5

Step-by-step explanation:

Step 1: We make the assumption that 200 is 100 % since it is our output value.

Step 2: We next represent the value we seek with x.

Step 3: From step 1, it follows that 100 % = 200.

Step 4: In the same vein, x % = 165 .

Step 5: This gives us a pair of simple equations:

100 % = 200(1).

x % = 165(2).

Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

100 % / x % = 200/165

Step 7: Taking the inverse (or reciprocal) of both sides yields

x/100 = 165/200

x = 82.5 %

3 0
3 years ago
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