What is a unit rate for meter per second if a car travels 274 m in 17 seconds

I need to fine the height of a triangular pyramid and I already have the volume and Area

Keith_Richards [23]

I’m not sure, but i think that you have to take the volume equation, and plug in the other variables (volume, area) to find the height

6 0

3 years ago

Rectangle J'K'L'M' shown on the grid is the image of rectangle JKLM after transformation. The same transformation will be applie

adoni [48]

Answer:

Location of T' on the coordinate axis will be (16,7).

T (6,4) → T' (16,7).

Step-by-step explanation:

coordinate vertices of points in rectangle JKLM are:

J (-8,-8)

K (-4,-8)

L (-4,-5)

M (-8,-5)

and coordinate vertices of points in rectangle J'K'L'M' are:

J' (2,-5)

K' (6,-5)

L' (6,-2)

M' (2,-2)

coordinate vertices of points in Quadrilateral STUV are:

S (1,4)

T (6,4)

U (4,6)

V (2,6)

transformation in coordinate vertices from rectangle JKLM to rectangle J'K'L'M' is:

J (-8,-8) → J' (2,-5)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

similarly for

K (-4,-8) → K' (6,-5)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -8 → -5 which means that the rectangle is shifting upwards by 3 units.

L (-4,-5) → L' (6,-2)

⇒ along x axis -4 → 6 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.

M (-8,-5) → M' (2,-2)

⇒ along x axis -8 → 2 which means that rectangle is shifting towards right by 10 units.

and along y axis -5 → -2 which means that the rectangle is shifting upwards by 3 units.

So, the location of T' of the Quadrilateral S'T'U'V' on the coordinate plane will be:

along x axis the Quadrilateral will shift towards right by 10 units

So, 6 → 6+10=16

and along y axis the Quadrilateral will shift upwards by 3 units

So, 4 → 4+3=7

⇒ T (6,4) → T' (16,7).

7 0

3 years ago

Read 2 more answers

A six-sided die is rolled 120 times. Fill in the expected frequency column. Then, conduct a hypothesis test at the 5% level to d

borishaifa [10]

Answer:

Die is not fair given that Pvalue< 0.05, hence we reject Null hypothesis

a) H0: Die = fair

b) Ha : Die ≠ fair

c) df = 5

Step-by-step explanation:

The expected frequency of every face values = 20

a) state Null hypothesis

H0: Die = fair

b) Alternate Hypothesis

Ha : Die ≠ fair

c) degree of freedom

df = ( n - 1 )

= ( 6 - 1 ) = 5

n = sample size ( number of faces a die has )

Note : After conducting hypothesis test

Pvalue ≈ 0.0026

test statistic ≈ 18.30

Hence we can conclude that die is not fair given that Pvalue < 0.05, hence we reject Null hypothesis

5 0

3 years ago

Select the two values of x that are roots of this equation.<br> X2 + 2x - 5 = 0

LenaWriter [7]

Answer:

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

Step-by-step explanation:

$x=\frac{-b±\sqrt{b^{2}-4ac } }{2a}$

Ignore the A before the ±. It wouldn't let me type it correctly.

x² + 2x - 5 = 0

a = 1

b = 2

c = - 5

$x=\frac{-2±\sqrt{2^{2}-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4-4((1)(-5)) } }{2(1)}$

$x=\frac{-2±\sqrt{4+20 } }{2(1)}$

$x=\frac{-2±\sqrt{24 } }{2}$

$x=\frac{-2±\sqrt{(2)(12) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(6) } }{2}$

$x=\frac{-2±\sqrt{(2)(2)(2)(3) } }{2}$

$x=\frac{-2±(\sqrt{2} )(\sqrt{2})(\sqrt{(2)(3) )} }{2}$

$x=\frac{-2±2\sqrt{6 } }{2}$

Two separate equations

$x=\frac{-2+2\sqrt{6 } }{2}$

$x=\frac{-2-2\sqrt{6 } }{2}$

$x=-1+\sqrt{6 }$

$x=-1-\sqrt{6 }$

7 0

3 years ago

50 POINTS Abigail is making a rectangular collage. She has 54 square photographs. Each photograph is 1 inch by 1 inch. She wants

Karo-lina-s [1.5K]

It easy, 9 * 54 = 486 Inches

6 0

4 years ago