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3 years ago

What is the probability of a customer buying carrots,?

Mathematics

2 answers:

earnstyle [38]3 years ago

8 0

OPTION 3: 10 percent

VARVARA [1.3K]3 years ago

6 0

Answer:

I think the probability of a customer buying carrots is 10.0

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What is the slope of y=5/2x - 4. and what is the y intercept

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Slope is 2/3

y-intercept is 1

Step-by-step explanation:

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2 years ago

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The length of a rectangular is 2/5 meter.It's width is 1/4 of its length .What is the perimeter of the rectangle?

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I think the answer is 2 13/20
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3 years ago

HELP!!!! <br><br> -5 3/4 - 3 1/2 = ?

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9.25 or 9 1/4

Step-by-step explanation:

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3 years ago

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Use the information to answer the following question.

Zanzabum

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Step-by-step explanation:

Since the difference between 0 and -10 is 10, this means that the difference between the diving board and the pool also has to be 10. Therefore, the diving board is 10 feet above the water since 0+10 is 10.

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3 years ago

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The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago