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AveGali [126]
1 year ago
12

What is the value of the expression below when x equals 5 6x3^ + 8x

Mathematics
1 answer:
Ghella [55]1 year ago
3 0

790

1) Since it's been given the expression 6x³+8x, let's plug into that the value for x=5

6x³+8x <em>Plug into that x =5</em>

6(5)³+8(5)

6(125) +8(5) <em>Distribute the factors</em>

<em>790</em>

<em />

2) So the answer is 790

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Answer:

<DEB= 125 degrees

Step-by-step explanation:

To get this, you would need to know all 2 angles of the triangle.

To find the first angle, simply do 180-107 to get 73(because supplementary angles add up to 180 degrees).

Next, 180-52(given angle)-73 to get 55 because the 3 angles of a triangle add up to 180(triangle angle sum theory).

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Consider the differential equation: xy′(x2+7)y=cos(x)+e3xy. Put the differential equation into the form: y′+p(x)y=g(x), determin
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Answer:

Linear and non-homogeneous.

Step-by-step explanation:

We are given that

\frac{xy'}{(x^2+7)y}=cosx+\frac{e^{3x}}{y}

We have to convert into y'+P(x)y=g(x) and determine P(x) and g(x).

We have also find type of differential equation.

y'=\frac{(x^2+7)y}{x}(cosx+\frac{e^{3x}}{y}}

y'=\frac{(x^2+7)cosx}{x}y+\frac{(x^2+7)e^{3x}}{x}

y'-\frac{cosx(x^2+7)}{x}y=\frac{e^{3x}(x^2+7)}{x}

It is linear differential equation because  this equation is of the form

y'+P(x)y=g(x)

Compare it with first order first degree linear differential equation

y'+P(x)y=g(x)

P(x)=-\frac{cosx (x^2+7)}{x},g(x)=\frac{e^{3x}(x^2+7)}{x}

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Homogeneous equation

\frac{dy}{dx}=\frac{f(x,y)}{g(x,y)}

Degree of f and g are same.

f(x,y)=(x^2+7)(ycosx+e^{3x}),g(x,y)=x

Degree of f and g are not same .

Therefore, it is non- homogeneous .

Linear and non-homogeneous.

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Answer:

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Step-by-step explanation:

We need to find LCM of 21,24 and 26

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