Question

8th/9th-95 POINTS+BRAINLIEST!!!!!!!! How do you write a quadratic equation in vertex form? Please explain the steps in simple language and use y=x²+6x+16 as an example.

Answer 1

So you find the a and b in (x-a)^2+b. A is 3 and b is 7.

Answer 2

Answer:

In vertex form: y = 1(x - (-3))² + 7

Vertex: Minimum (-3, 7)

Explanation:

Vertex form: y = a(x - h)² + k

Completing square (rules) :

1st rule: (x + d)² = x² + 2dx + d²    and   (x - d)² = x² - 2dx + d²

2nd rule: x² + 2dx = (x + d)² - d²   and  x² - 2dx = (x - d)² - d²

Given equation:

y = x² + 6x + 16

y = x² + 2(3)x + 3² + 7

y = (x + 3)² + 7

Into vertex form:

y = 1(x - (-3))² + 7

From this identify:

a = 1, h = -3, k = 7

Solution, vertex of this equation: Minimum (-3, 7)