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jeka57 [31]
1 year ago
6

Use point-slope form to write the equation of a line that passes through the point (16,-14) with slope 11.

Mathematics
1 answer:
OlgaM077 [116]1 year ago
3 0

The required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.

What is the slope of the line?

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,

The point-slope of the equation of the line is given by,

y - y₁ = m(x - x₁)

Put the values in the above equation of the line

y - 5 = -4 (x - (-1))

y - 5 = -4 (x + 1)

Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Learn more about slopes visit:

brainly.com/question/3605446

#SPJ1

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2 years ago
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Given:

The figure of a rhombus QRST.

To find:

A. The value of x.

B. The measure of angle RQP.

Solution:

A. We need to find the value of x.

We know that the diagonals of a rhombus are perpendicular bisectors. It means the angles on the intersection of diagonals are right angles.

m\angle RPS=90^\circ                       [Right angle]

(5x+15)^\circ=90^\circ

(5x+15)=90

5x=90-15

5x=75

Divide both sides by 5.

x=\dfrac{75}{5}

x=15

Therefore, the value of x is 15.

B. We need to find the measure of angle RQP.

From the given figure, it is clear that

m\angle RQP=(2x+3)^\circ

Putting x=15, we get

m\angle RQP=(2(15)+3)^\circ

m\angle RQP=(30+3)^\circ

m\angle RQP=33^\circ

Therefore, the measure of angle RQP is 33 degrees.

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2 years ago
Find the length of the rectangle side
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Consider the offered option:
if suppose, that unknown side is '?', then
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