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jeka57 [31]
1 year ago
6

Use point-slope form to write the equation of a line that passes through the point (16,-14) with slope 11.

Mathematics
1 answer:
OlgaM077 [116]1 year ago
3 0

The required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.

What is the slope of the line?

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,

The point-slope of the equation of the line is given by,

y - y₁ = m(x - x₁)

Put the values in the above equation of the line

y - 5 = -4 (x - (-1))

y - 5 = -4 (x + 1)

Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Learn more about slopes visit:

brainly.com/question/3605446

#SPJ1

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Step-by-step explanation:

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3 years ago
I need help on questions 48 and 49.
xenn [34]
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3 years ago
In square ABCD, diagonals AC and DB intersect at point E, m∠EBC=(3x+9y)°, and m∠EAB=(5x+5y)°.
telo118 [61]

Answer:

Step-by-step explanation:

m∠EBC = 45°

3x + 9y = 45

Divide the entire equation by 3

x + 3y = 15 --------------------(I)

m∠EAB = 45

5x + 5y = 45

Divide the entire equation by 5

x +y = 9 -------------(II)

Multiply equation (II) by (-1)

(I)             x + 3y = 15

(II)*(-1)    <u> - x -  y   = -9</u>   {Now add}

                   2y   = 6

                     y = 6/2

                     y = 3

Plugin y = 3 in equation (I)

x + 3*3 = 15

x + 9 = 15

x = 15 - 9

x = 6

6 0
2 years ago
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