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jeka57 [31]
1 year ago
6

Use point-slope form to write the equation of a line that passes through the point (16,-14) with slope 11.

Mathematics
1 answer:
OlgaM077 [116]1 year ago
3 0

The required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Given that, To determine an equation in point-slope form for the line that passes through the point with the given slope. point: (-1, 5) and m=-4.

What is the slope of the line?

The slope of the line is a tangent angle made by line with horizontal. i.e. m =tanx where x in degrees.

Here,

The point-slope of the equation of the line is given by,

y - y₁ = m(x - x₁)

Put the values in the above equation of the line

y - 5 = -4 (x - (-1))

y - 5 = -4 (x + 1)

Thus, the required point-slope form of the equation of the line is y - 5 = -4(x + 1).

Learn more about slopes visit:

brainly.com/question/3605446

#SPJ1

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What does the fundamental theorem of algebra illustrate?
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The fundamental theorem of algebra guarantees that a polynomial equation has the same number of complex roots as its degree.

Step-by-step explanation:

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We have to find the roots of this given equation.

If a quadratic equation is of the form ax^{2}+bx +c=0

Its roots are \frac{-b+\sqrt{b^{2}-4ac } }{2a} and \frac{-b-\sqrt{b^{2}-4ac } }{2a}

Here the given equation is 2x^{2}-4x-1 = 0

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c = -1

If the roots are x_{1} and x_{2}, then

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                       = \frac{4 +\sqrt{24}}{4}

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x_{2} = \frac{-2-\sqrt{(-4)^{2}-4\times 2\times (-1)}}{2\times 2}

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