Answer:
x1=-3+i*sqrt(13)
x2=-3-i*sqrt(13)
Step-by-step explanation:
x^2 +6x=-22
x^2 +6x+22=0 (Quadratic equation)
a=1, b=6, c=22
x1=(-b+sqrt(b^2-4ac)) /2a
x1=(-6+sqrt(6^2 -4*1*22))/2*1
x1=(-6+sqrt(36-88))/2
x1=(-6+sqrt(-52))/2
x1=(-6+sqrt(52i^2))/2...... i^2=-1
x1=(-6+sqrt (4*13i^2))/2
x1=(-6+2i*sqrt(13))/2
x1=-3+i*sqrt(13)
x2=(-b-sqrt(b^2-4ac)) /2a
x2=-3-i*sqrt(13)
Answer:
A = 10.27cm²
Step-by-step explanation:
Let's represent the width as x,
therefore since the length is 4 more than 3 times the width, it can be represent as 3x + 4, Perimeter = 18.4cm
Perimeter of a rectangle = 2(L + B)
width = 1.3cm
Length = 3x + 4 = 3*1.3 + 4 = 7.9cm
Area of a rectangle = length x width
A = 7.9 * 1.3 = 10.27cm²
Answer:
3 and 30
Step-by-step explanation:
Answer:
a) (x/7)^1/9=y
Step-by-step explanation:
f(x) = 7x^9
x/7= 7y^9/7
(x/7)^1/9=(y^9)^1/9
(x/7)^1/9=y
f^-1(x) is a fuction because it passes the vl test
Answer:
Ore 1 = 28 tons
Ore 2 = 8 tons
Cost = $3480
Explanation:
Complete solution is provided in attached pictures. The Objective function line is dragged to the lowest edge of feasible region to obtain the optimum solution of (28,8).
That is 28 tons of Ore type-1 and 8 tons of Ore Type-2 should be ordered to incur minimum cost of $3480.