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yarga [219]
3 years ago
6

A truck can be rented from Company A for ​$100 a day plus ​$0.60 per mile. Company B charges ​$30 a day plus ​$0.80 per mile to

rent the same truck. Find the number of miles in a day at which the rental costs for Company A and Company B are the same.
Mathematics
1 answer:
Grace [21]3 years ago
4 0

Answer:

80+ 0.3x = 60 + 0.4x

20 = 0.1x

x = 200

Therefore, at 150 miles, the best deal changes companies

Step-by-step explanation:

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The graph of a line passes through the points (0, -2) and (6.0). What is
9966 [12]

Answer:

y=\frac{1}{3}x-2

Step-by-step explanation:

The equation of a line is given in the form  y=mx+b

Where

m is the slope with formula  m=\frac{y_2-y_1}{x_2-x_1}

and

b is the y-intercept [y axis cutting point of line]

Given the two points (0, -2) and (6,0),

x_1 = 0

y_1 = -2

x_2 = 6

y_2 = 0

Now, we find m using formula:

m=\frac{0+2}{6-0}=\frac{1}{3}

Now we have

y=\frac{1}{3}x+b

Finding b, we plug in any (x,y) point. Lets put (6,0) and find b:

y=\frac{1}{3}x+b\\0=\frac{1}{3}(6)+b\\0=2+b\\b=-2

Thus,

equation of line = y=\frac{1}{3}x-2

5 0
3 years ago
1. The current ratio (assets/liabilities) of company X is 3.1. Given that the current assets are $186000, find the current liabi
katrin [286]
<span>1. The current ratio (assets/liabilities) of company X is 3.1. Given that the current assets are $186000, find the current liabilities:

Assets = A
Liabilities = L

A / L = 3.1 => L = A / 3.1

A =  186000 => L = 18600 / 3.1 = 6000

Answer: $ 6000

2. The board of directors determines that the current ratio must never be below 2.6. What is the maximum amount that the company can borrow?


A/L ≥ 2.6

=> L ≤ A / 2.6

=> L ≤ 186000 / 2.6

L ≤ 71538.46

Answer: $71538.46
</span>
6 0
3 years ago
Suppose the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1
denis23 [38]
Given that <span>the weights of farmer carl's potatoes are normally distributed with a mean of 8.0 ounces and a standard deviation of 1.1 ounces.

The probability of a normally distributed data between two values (a, b) is given by:

P(a\ \textless \  X\ \textless \  b)=P\left(z\ \textless \  \frac{b-\mu}{\sigma/\sqrt{n}} \right)-P\left(z\ \textless \  \frac{a-\mu}{\sigma/\sqrt{n}} \right) \\  \\ =P(7.5\ \textless \ X\ \textless \ 8.5)=P\left(z\ \textless \  \frac{8.5-8.0}{1.1/\sqrt{6}} \right)-P\left(z\ \textless \  \frac{7.5-8.0}{1.1/\sqrt{6}} \right) \\  \\ =P(z\ \textless \ 1.113)-P(-1.113)=0.8672-0.1328=0.7344</span>
6 0
3 years ago
How do you do this problem?
exis [7]
X=-.5, it’s less than 0, and concave up & increasing in this situation are the same.
3 0
3 years ago
Read 2 more answers
The value of x in the equation log(x-1)9=2 is
mel-nik [20]
\log_{(x-1)} 9=2

the domain:
x-1 >0 \ \land \ x-1 \not=1 \\&#10;x>1 \ \land \ x \not= 2 \\&#10;x \in (1; 2) \cup (2;+\infty)

the equation:
\log_{(x-1)}9=2 \\&#10;(x-1)^2=9 \\&#10;\sqrt{(x-1)^2}=\sqrt{9} \\&#10;|x-1|=3 \\&#10;x-1=3 \ \lor \ x-1=-3 \\&#10;x=4 \ \lor \ x=-2

4 is in the domain
-2 is not in the domain

The answer:
x=4

***
Also, the answer in 13 is {8}. -3 is not in the domain. Replace x with -3 and you'll see:
x=\sqrt{5x+24} \\&#10;-3=\sqrt{5 \times (-3)+24} \\&#10;-3=\sqrt{-15+24} \\&#10;-3=\sqrt{9} \\&#10;-3=3
It's not true so -3 isn't a solution to this equation.
4 0
3 years ago
Read 2 more answers
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