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Musya8 [376]
2 years ago
14

3 PARTS FOR 40 PIONTS AND BRIANLY, TYSM IF YOU ANSWER WITH LOVE AND CARE.

Mathematics
1 answer:
pshichka [43]2 years ago
6 0

The domain of the function is [0.70, 2.55]

  • The range is [1.04, 2.56]
  • The domain is the set of x values and the range is the set of y values

<h3>How to determine the domain of the function?</h3>

From the question, we have the following parameters that can be used in our computation:

(0.70)(1.04)(1.15)(1.38)(1.86)(1.70)(2.55)(1.29)(2.22)(2.56)

When represented as a table, we have:

x            y

0.70    1.04

1.15      1.38

1.86     1.70

2.55     1.29

2.22    2.56

Remove the y values

So, we have

x = {0.70, 1.15, 1.86, 2.55, 2.22}

As an interval notation, we have: [0.70, 2.55]

This set of values is the domain

<h3>How to determine the range of the function?</h3>

In (a), we have the following table of values

x            y

0.70    1.04

1.15      1.38

1.86     1.70

2.55     1.29

2.22    2.56

Remove the x values

So, we have

y = {1.04, 1.38, 1.70, 1.29, 2.56}

As an interval notation, we have: [1.04, 2.56]

This set of values is the range

<h3>How the domain and the range are calculated</h3>

To determine the domain, we make use of the x values

While the y values are used to represent the range

Read more about domain and range at

brainly.com/question/2264373

#SPJ1

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Find missing angle.
Vsevolod [243]
I don’t really know exactly to what degree you need to put in your solution. But I rounded to the nearest tenth degree.
A = 112 degrees
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C= 40
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b= 14 (side opposite b)
c= 19.2 (side opposite c)

HOW TO SOLVE:
c= law of sines, so c/sin(40) = 14/sin(28), multiply both sides by sin(40) so c can be isolated and solved for. c = 14sin(40)/sin(28). Plug into calculator then get answer. c is approximately 19.2.
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Solve the given differential equation by undetermined coefficients. y'' 4y = 7 sin(2x)
kherson [118]

The solution to the given differential equation is yp=−14xcos(2x)

The characteristic equation for this differential equation is:

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The roots of the characteristic equation are:

s=±2i

Therefore, the homogeneous solution is:

yh=c1sin(2x)+c2cos(2x)

Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:

yp=Axsin(2x)+Bxcos(2x)

If you take the second derivative of the equation above for  yp , and then substitute that result,  y′′p , along with equation for  yp  above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side,  sin(2x) , you will find:

A=0

B=−14

Therefore,

yp=−14xcos(2x)

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