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TEA [102]
3 years ago
11

Michael is a basketball player who regularly shoots sets of 2 free-throws. Suppose that each shot has probability 0.60. , point,

6 of being made, and the results of the shots are independent.
Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

0.1306

Step-by-step explanation:

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

n = total number of sample spaces = number of free throws

x = Number of successes required = 6

p = probability of success = 0.60

q = probability of failure = 1 - 0.60 = 0.40

P(X = 6) = ⁷C₆ (0.6)⁶ (0.4)⁷⁻⁶ = 0.1306368 = 0.1306

Hope this Helps!!!

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3 years ago
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4(1+.5m)=7m<br>what is m?<br>​
RUDIKE [14]
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A salespersons commission rate is 4% what is the commission from the sale of $36,000 worth of furnaces use pencil and paper supp
Mnenie [13.5K]

Answer:

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7 0
3 years ago
there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap
valkas [14]

21 chaperones are needed for 420 students.

Step-by-step explanation:

No. of juniors = 148

No. of seniors = 272

Total = 148+272 = 420 students

3 chaperones = 60 students

1 chaperone = \frac{60}{3}=20\ students

Ratio of chaperon to students = 1:20

Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

Ratio of chaperones to students :: Ratio of chaperons to students

1:20::x:420

Product of mean = Product of extreme

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Dividing both sides by 20

\frac{20x}{20}=\frac{420}{20}\\x=21

21 chaperones are needed for 420 students.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

3 0
3 years ago
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blagie [28]

Partial products are the products obtained during the intermediate stages in order to complete a multiplication process.

Consider 68 \times 43, we have to determine the partial products in this.

Now, 68 \times 43

Expanding this, we get

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= 2924

Hence, 8 \times 40=320 and 8 \times 3 = 24 are the required partial products in the product of 68 and 43.

So, Option 3 and 4 are the correct answers.

3 0
2 years ago
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