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max2010maxim [7]
1 year ago
7

Consider the following proability density function: f(x) = { kx. 0<= x< 2, k(4-x). 2<= x <=4, 0. otherwise. find the

value of k for which f(x) is a valid probability density funcion
Mathematics
1 answer:
Gnesinka [82]1 year ago
4 0

The value of K for which f(x) is a valid probability density function is 1/4.

<h3>How to solve for the value of K</h3>

\int\limits^4_0 {fx(x)} \, dx =1

\int\limits^2_0 {Kx} \, dx +\int\limits^4_2 {K(4-x)} \, dx =1

K[\frac{2^2}{2} -0]+[K[4(4-2)-(\frac{4^2}{2} -\frac{2^2}{2} )]=1

open the equation

K\frac{4}{2}+K[8 - (\frac{16}{2}  -\frac{4}{2} )] = 1\\

2K+K[\frac{4}{2} ]=1

2K + 2K = 1

4K = 1

divide through by 4

K = 1/4

Read more on probability density function here

brainly.com/question/15714810

#SPJ4

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Answer:

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