sub x=1 into f(x),
remainder= 1^3+2(1)^2-5(1)-6= -8
since remainder≠0, x=1 is not a root of the function
sub x=-1,
remainder = (-1)^3+2(-1)^2-5(-1)-6= 0
by remainder theorem,
x=-1 is a root of f(x)
hence, the correct ans is c
The solution to the inequality 6m + 2 > -27 is m > -4.33
The solution to the inequality 8(p-6)>4(p-4) is p > 8
The given inequality is:
6m + 2 > - 27
Subtract 2 to both sides of the inequality
6m + 2 - 2 > -27 - 2
6m > -29
Divide both sides by 6
For the inequality 8(p-6)>4(p-4)
Expand the inequality using the distributive rule
8p - 48 > 4p - 16
Collect like terms
8p - 4p > -16 + 48
4p > 32
Divide both sides of the inequality 4
The solution to the inequality 6m + 2 > -27 is m > -4.33
The solution to the inequality 8(p-6)>4(p-4) is p > 8
Learn more here: brainly.com/question/15816805
X + x+2 + x+4 + x+6 +x+8 + x+10 + x+12 + x+14 + x+16 + x+18 = 1190
Now simplify
10x + 90 = 1190
10x = 1100
x = 110
Now plug in 110 for x
Answer:
Step-by-step explanation:
f(x) = 4-x
g(x) = h+k
g(f(x)) = 2-16x+26
so put f(x) in g(x)
h+k
h((4-x)(4-x) + k
h(-8x+16)+k
if h = 2 , then
2-16x+32 + k
and we want 26 instead of 32 so subtract 6 so K = (-6)
2-16x+32 + (-6)
2-16x+32 - 6
2-16x+26
h=2
k=(-6)