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PIT_PIT [208]
2 years ago
12

An angle measures 62.4° more than the measure of its supplementary angle. What is the measure of each angle?

Mathematics
1 answer:
Klio2033 [76]2 years ago
5 0

Answer:

Step-by-step explanation:

If an angle measures x degrees, the measure of its supplement is (180-x) degrees.

This means that x-62.4 = 180-x, meaning that x=121.2.

So, the angles are 121.2 and 58.8 degrees.

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Answer:

11th month which is November

Step-by-step explanation:

1860 + 45(m - 1) = 2310

1860 + 45m - 45 = 2310

1815 + 45m = 2310

45m = 495

m = 11

8 0
3 years ago
A number that divided by 3 leaves 2, divided by 5 leaves 3 and divided by 7 leaves 2. What is the number?
Bogdan [553]
X/3=2 
x=6

x/5=3
x=15

x/7=2
x=14

Each time, you multiply both sides by the denominator.

Hope this helps :)
7 0
3 years ago
If joe had 35 apples and sold 3 people 5 each how many does he have
Wewaii [24]

Answer: Joe has 20 remaining apples

[to get your answer, subtract, 35 - 5 - 5 - 5]

6 0
2 years ago
Read 2 more answers
Which group of numbers is listed from least to greatest?
Karolina [17]

Answer:

The answer should be B

Step-by-step explanation:

7 0
2 years ago
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$13,957 is invested, part at 7% and the rest at 6%. If the interest earned from the amount invested at 7% exceeds the interest e
ch4aika [34]

Answer:

The Amount invested at 7% interest is $12,855

The Amount invested at 6% interest = $1,102  

Step-by-step explanation:

Given as :

The Total money invested = $13,957

Let The money invested at 7% = p_1  = $A

And The money invested at 6% = p_2 = $13957 - $A

Let The interest earn at 7% = I_1

And The interest earn at 6% = I_2

I_1 -  I_2 = $833.73

Let The time period = 1 year

Now,<u> From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal\times \textrm rate\times \textrm time}{100}

Or,  I_1 = \dfrac{\textrm p_1\times \textrm 7\times \textrm 1}{100}

Or,  I_1 = \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100}

And

I_2 = \dfrac{\textrm p_2\times \textrm 6\times \textrm 1}{100}

Or,  I_2 = \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100}

∵  I_1 -  I_2 = $833.73

So, \dfrac{\textrm A\times \textrm 7\times \textrm 1}{100} -  \dfrac{\textrm (13,957 - A)\times \textrm 6\times \textrm 1}{100} = $833.73

Or, 7 A - 6 (13,957 - A) = $833.73 × 100

Or, 7 A - $83,742 + 6 A = $83373

Or, 13 A = $83373 + $83742

Or, 13 A = $167,115

∴ A = \dfrac{167115}{13}

i.e A = $12,855

So, The Amount invested at 7% interest = A = $12,855

And The Amount invested at 6% interest = ($13,957 - A) = $13,957 - $12,855

I.e The Amount invested at 6% interest = $1,102

Hence,The Amount invested at 7% interest is $12,855

And The Amount invested at 6% interest = $1,102   . Answer

8 0
3 years ago
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