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barxatty [35]
1 year ago
6

the goal to be a non-starter for the team as they have never mishandled fewer than 200 bags, let alone hit the goal of 100 bags.

this means that there .
Mathematics
1 answer:
bixtya [17]1 year ago
6 0

The goal seems to be a non-starter for the team as they have never mishandled fewer than 200 bags, let alone hitting the goal of 100 bags. Based on expectancy theory, this is a(n) expectancy.

<h3>What is meant by expectancy theory?</h3>

The expectation theory asserts that people are more motivated to put in extra effort when they feel that their efforts will be acknowledged and rewarded (Vroom, 1964). Businesses that implement performance-based remuneration may therefore expect advancements. Performance-based compensation can tie benefits to the quantity of work that employees produce.

The three components of the expectation theory are valence, instrumentality, and expectancy. Expectancy is the likelihood that a particular effort will produce the performance or results that are sought. Awarded that they handled 200 bags improperly, this team is a non-starter, thus the goal is given for them. According to expectation theory, there is a 100 percent chance of hitting the ball. Consequently, this is an expectation problem.

Therefore, the correct answer is option a) expectancy.

The complete question is:

The goal seems to be a non-starter for the team as they have never mishandled fewer than 200 bags, let alone hitting the goal of 100 bags. Based on expectancy theory, this is a(n) ______ problem.

a) expectancy

b) valence

c) outcome

d) instrumentality

e) equity

To learn more about expectancy theory refer to:

brainly.com/question/13891821

#SPJ4

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a) Windows on the International Space Station are shown below. Suppose the long base of the window is 15.2 feet and the short ba
statuscvo [17]
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6 0
3 years ago
7 is 10% of y. What was franklin's age
Lapatulllka [165]
Franklin is 70 years of age since 7 is 10% so 10 x 7 = 70
8 0
3 years ago
Micheal solved this inequality as shown: step 1: -6(x + 3) + 10 &lt; -2 step 2: -6x - 18 + 10 &lt; -2 step 3: -6x - 8 &lt; -2 st
Anastaziya [24]
<h3>Answer:   addition property of inequality</h3>

================================================

Explanation:

These are the steps to focus on

step 3: -6x - 8 < -2

step 4: -6x < 6

The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.

That property has four forms

  1. If a > b then a + c > b+c
  2. If a < b then a+c < b+c
  3. If a \ge b then a + c \ge b+c
  4. If a \le b then a+c \le b+c

It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c

We add the same thing to both sides to keep things balanced.

8 0
2 years ago
Find the absolute maximum and minimum values of the function below. f(x) = x3 − 9x2 + 3, − 3 2 ≤ x ≤ 12 Solution Since f is cont
Neko [114]

Answer:

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

Step-by-step explanation:

The correct statement is described below:

Find the absolute maximum and minimum values of the function below:

f(x) = x^{3}-9\cdot x^{2}+ 3, 2 \leq x \leq 12

Given that function is a polynomial, then we have the guarantee that function is continuous and differentiable and we can use First and Second Derivative Tests.

First, we obtain the first derivative of the function and equalize it to zero:

f'(x) = 3\cdot x^{2}-18\cdot x

3\cdot x^{2}-18\cdot x = 0

3\cdot x \cdot (x-6) = 0 (Eq. 1)

As we can see, only a solution is a valid critical value. That is: x = 6

Second, we determine the second derivative formula and evaluate it at the only critical point:

f''(x) = 6\cdot x -18 (Eq. 2)

x = 6

f''(6) = 6\cdot (6)-18

f''(6) =18 (Absolute minimum)

Third, we evaluate the function at each extreme of the given interval and the critical point as well:

x = 2

f(2) = 2^{3}-9\cdot (2)^{2}+3

f(2) = -25

x = 6

f(6) = 6^{3}-9\cdot (6)^{2}+3

f(6) = -105

x = 12

f(12) = 12^{3}-9\cdot (12)^{2}+3

f(12) = 435

There are an absolute minimum (x = 6) and an absolute maximum (x = 12).

6 0
3 years ago
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