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Semenov [28]
2 years ago
6

Micheal solved this inequality as shown: step 1: -6(x + 3) + 10 < -2 step 2: -6x - 18 + 10 < -2 step 3: -6x - 8 < -2 st

ep 4: -6x < 6 step 5: x > -1. what property justifies the work shown between step 3 and 4?
Mathematics
1 answer:
Anastaziya [24]2 years ago
8 0
<h3>Answer:   addition property of inequality</h3>

================================================

Explanation:

These are the steps to focus on

step 3: -6x - 8 < -2

step 4: -6x < 6

The move from the third step to the fourth step has us adding 8 to both sides. Therefore, we use the addition property of inequality.

That property has four forms

  1. If a > b then a + c > b+c
  2. If a < b then a+c < b+c
  3. If a \ge b then a + c \ge b+c
  4. If a \le b then a+c \le b+c

It's similar to the idea of starting with a = b, then adding c to both sides to get a+c = b+c

We add the same thing to both sides to keep things balanced.

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Given f() = -4x + 3, find f(-3)
Fittoniya [83]

Answer:

The answer is 15

Step-by-step explanation:

f(x) = -4x + 3, f(-3)

f(-3) = -4x + 3

f(-3) = -4(-3) + 3

f(-3) = 12 + 3

f(-3) = 15

Thus, The answer is 15

8 0
2 years ago
Read 2 more answers
Help me please??!!!
kaheart [24]

Answer:

its the second 1

Step-by-step explanation:

i had last week and got a 88.87%

6 0
3 years ago
The circumference for a circle that has a radius or 7 inches is
lidiya [134]
Circumference
C=2πr
C=2(3.14)(7)
C=(3.14)(14)
C=43.96
7 0
3 years ago
I would like to create a rectangular vegetable patch. The fencing for the east and west sides costs $4 per foot, and the fencing
Anestetic [448]
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y.  the dimensions you want are therefore x and y.

The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y.  We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.



The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128.  Let's reduce this by dividing all three terms by 4:  2x + y = 32.

Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32.  The formula for area is A = L * W.  Solving 2x + y = 32 for y, we get y = -2x + 32.

We can now eliminate y.  The area of the patch is (x)(-2x+32) = A.  We want to maximize A.

If you're in algebra, find the x-coordinate of the vertex of this quadratic equation.  Remember the formula x = -b/(2a)?  Once you have calculated this x, subst. your value into the formula for y:  y= -2x + 32.

Now multiply together your x and y values to obtain the max area of the patch.


If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero.  This approach should give you the same x value as before; the corresponding y value will be the same;  y=-2x+32.

Multiply x and y together.  That'll give you the maximum possible area of the garden patch.
5 0
4 years ago
In the image shape ABCD is similar to shape MNOP
DiKsa [7]

Answer:

10.5

Step-by-step explanation:

cross multiplying:

?/12 = 14/16

16? = 168

? = 10.5

4 0
3 years ago
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