2 years ago

Can someone please help me

Mathematics

1 answer:

viktelen [127]2 years ago

4 0

Answer:

Y=-3x+7

Step-by-step explanation:

it hit the y axis at 7

And it is going down by 3

You might be interested in

I really need HELP I have 10 minutes to answer!!!!!

julsineya [31]

Monday and Tuesday because the second spot after the decimal point is the hundredths spot.

7 0

3 years ago

5.) 3x^2 - 13x + 4 = 0

Anna71 [15]

Answer:

Answer:

x= 1/3 or x=4

Step-by-step explanation:

Let's solve your equation step-by-step.

3x2−13x+4=0

Step 1: Factor left side of equation.

(3x−1)(x−4)=0

Step 2: Set factors equal to 0.

3x−1=0 or x−4=0

x= 1/3or x=4

plz give brainlyest

7 0

3 years ago

Solve for the width in the formula for the area of a rectangle.

madam [21]

A = L * W
A / L = W <==

when A = 42 and W = 16.8
A / L = W
42/16.8 = W
2.5 = W <=== width = 2.5 inches

4 0

3 years ago

Read 2 more answers

Round decimal to the nearest one . Then add 7.91+21.9=

Arte-miy333 [17]

7.91 = 8 21.9 = 22

8 + 22 = 30

7 0

3 years ago

Read 2 more answers

Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean

Zinaida [17]

Answer:

$E[R]$ = 99 Ω

$\sigma_R$ = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, $E[R] = \frac{a+b}{2} = \frac{95+103}{2} = \frac{198}{2}$ = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

$V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333$

Hence,

The standard deviation of resistance, $\sigma_R = \sqrt{V(R)} = \sqrt5.333$ = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

$z_1 = \frac{102-99}{2.3094} = 1.299$

$z_2 = \frac{98-99}{2.3094} = -0.433$

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0

4 years ago