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3 years ago

14

What's the largest 6-digit multiple of 5 that has all different digits? I'll give Brainliest to anyone who helps.

1 answer:

JulsSmile [24]3 years ago

3 0

Answer:

987650

Step-by-step explanation:

<u>The largest 6-digit number is: </u>

999999

We need all digits different and the last one 0 or 5 because the number is the multiple of 5.

9876 are the first 4 digits and the last two 50 or 45, we'll chose 50 as 45 is smaller.

<u>So the number is:</u>

987650

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What is the value of x?<br><br><br><br> Enter your answer in the box.

Grace [21]

The shapes are similar.
When two figures are similar, the ratios of the lengths of their corresponding sides are equal.
Therefore,
$\frac{42}{(15 + 42)} = \frac{x}{10 + x}$

Simplify:
$\frac{42}{57} = \frac{x}{10 + x}$
Cross multiply:
42(10+x) = 57x
420 + 42x = 57x
420 = 57x - 42x
420 = 15x
x = (420÷15)
x = 28

3 0

3 years ago

Are the ratios 1 : 3 and 3 : 1 equivalent? Why or why not?

Rainbow [258]

Answer: no

Step-by-step explanation:

no. one is the fraction 1 / 3 and the other is the fraction 3 / 1

6 0

2 years ago

Tamia is collecting boxes to help her friend move. She found a box that is 8 ft wide, 2 ft high, and 4 ft long how much space wo

Arada [10]

Answer: $64\ ft^3$

Step-by-step explanation:

Given

The dimension of the box is

$\text{width w=}8\ ft\\\text{height h=}2\ ft\\\text{length l=}4\ ft$

Space occupied by the box is equal to its volume i.e.

$\Rightarrow V=l\times b\times h\\\Rightarrow V=4\times 8\times 2\\\Rightarrow V=64\ ft^3$

The volume of the box is $64\ ft^3$ .

4 0

2 years ago

7. In a state lottery, a player must choose 8 of the numbers from 1 to 40. The lottery commission then performs an experiment th

Vlad1618 [11]

Answer:a) P(8 of the players numbers are drawn)=1.3×10^-8

b) P(7 of the players number are drrawn)=3.33×10^-c) P(at least 6 of the players number were drawn)=1.84×10^-4

Step-by-step explanation:

Players has 8 combinations of numbers from 1-40. The outcome S contains all the combinations of 8 out of 40

a) P(8 of the players numbers are drawn)= 1/40/8= 1.3×10^-8

There are one in hundred million chances that the draw numbers are precisely the chosen ones.

b) Number of ways of drawing 78 selected numbers from 1-40=8×(40-7)

8×32

P(7 of the players number are drawn)=8×32/40 =3.33×10^-6.

There are approximately 300,000 chances that 7 of the players numbers are chosen

c) P(at least 6 players numbers are drawn)= 32/2×(8/6) ways to draw.

P(at least 6 players numbers are drawn)=P(all 8 chosen are drawn)+P(7 players numbers drawn)+P(6 chosen are drawn) = 1+ 8 x32/40/8 +[8\6 ×32/2]

P(at least 6 players numbers are drawn) = 1.84×10^-4.

There are approximately 5400chances that at least6 of the numbers drawn are chosen by the player.

5 0

3 years ago

Need help with this problem

Zanzabum

Answer:

C. Priya needs to charge at least $21 per bracelet.

Step-by-step explanation:

$117b - 505 \ge 1952$

Add 505 to both sides.

$117b \ge 2457$

Divide both sides by 117.

$b \ge 21$

Answer: C. Priya needs to charge at least $21 per bracelet.

7 0

3 years ago