Step-by-step explanation:
2feet
feet
feet
feet
feet
feet
feet
2
2
2
2
2
2
Answer:confounding variable
Step-by-step explanation:
Answer:
-3
Step-by-step explanation:
We're told that
![P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995](https://tex.z-dn.net/?f=P%28A%29%3D%5Cdfrac1%7B200%7D%3D0.005%5Cimplies%20P%28A%5EC%29%3D0.995)
![P(B\mid A)=0.7](https://tex.z-dn.net/?f=P%28B%5Cmid%20A%29%3D0.7)
![P(B\mid A^C)=0.05](https://tex.z-dn.net/?f=P%28B%5Cmid%20A%5EC%29%3D0.05)
a. We want to find
. By definition of conditional probability,
![P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%5Cmid%20B%29%3D%5Cdfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D)
By the law of total probability,
![P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)](https://tex.z-dn.net/?f=P%28B%29%3DP%28B%5Ccap%20A%29%2BP%28B%5Ccap%20A%5EC%29%3DP%28B%5Cmid%20A%29P%28A%29%2BP%28B%5Cmid%20A%5EC%29P%28A%5EC%29)
Then
![P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657](https://tex.z-dn.net/?f=P%28A%5Cmid%20B%29%3D%5Cdfrac%7BP%28B%5Cmid%20A%29P%28A%29%7D%7BP%28B%5Cmid%20A%29P%28A%29%2BP%28B%5Cmid%20A%5EC%29P%28A%5EC%29%7D%5Capprox0.0657)
(the first equality is Bayes' theorem)
b. We want to find
.
![P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984](https://tex.z-dn.net/?f=P%28A%5EC%5Cmid%20B%5EC%29%3D%5Cdfrac%7BP%28A%5EC%5Ccap%20B%5EC%29%7D%7BP%28B%5EC%29%7D%3D%5Cdfrac%7BP%28B%5EC%5Cmid%20A%5EC%29P%28A%5EC%29%7D%7B1-P%28B%29%7D%5Capprox0.9984)
since
.
Answer:
There is one point: A (x, y) = (2, 0)
Step-by-step explanation:
A point of the square OABC is invariant only if its location coincides with location of the rotation axis, that is, that such point experiments only rotation, no translation in any form. The center of rotation coincides with the location of one of the vertices of the square and, therefore, there is one invariant point on the perimeter: A (x, y) = (2, 0)